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In triangle ABC, given (a ^ 2-C ^ 2) ^ 2 = B ^ 2 (2C ^ 2-B ^ 2), find the size of angle C
Given that three sides a, B and C of triangle ABC satisfy the equation a ^ 2 + B ^ 2 + 2C ^ 2 = 4A + 6B + 8c-21, the shape of triangle ABC is determined
Given that three sides a, B and C of triangle ABC satisfy the equation a ^ 2 + B ^ 2 + 2C ^ 2 = 4A + 6B + 8c-21, the shape of triangle ABC is judged
Distribution method
（a-2)^2+（b-3)^2+2(c-2)^2=0
a=2,b=3,c=2
So it's an isosceles triangle
a^2+b^2+c^2-4a+6b-2c+14=0
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