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A rectangular iron sheet with a width of 20 DM is welded into a water tank without cover after subtracting the cube with a side length of 5 DN from its four corners. The volume of the water tank is known to be 750 DM3, and the volume of the iron sheet used in the water tank is calculated
The width of the tank is 20-5-5 = 10 decimeters
Then the tank height is 5 decimeters
So the tank length = 750 △ 10 △ 5 = 15 decimeters
So the length of the rectangular sheet is 15 + 5 + 5 = 25 decimeters
So the area of iron sheet for water tank is 25 × 20-5 × 5 × 4 = 400 square decimeters
A piece of square iron sheet with a side length of 20 cm is planned to cut off four small squares from four corners, and then fold and weld them into a rectangular water tank without cover. Please design a welding method with a volume greater than 500, and calculate the volume of the water tank and the utilization rate of this sheet of iron sheet?
In the four corners of this sheet of iron, cut four small squares of 2cm × 2cm respectively, and then fold four sides with height of 2 in the same direction. Finally, weld the outside of the four 2cm long corner seams! The utilization rate of sheet iron is 96%
A piece of square iron sheet with side length of 12 decimeters can be welded into a cube bucket just after the square of the same size is cut off from its four corners
A square iron sheet with side length of 12 decimeters can be welded into a cube bucket after the square of the same size is cut off from its four corners
The edge length of this cube is 12 / 3 = 4 decimeters
The volume is: 4 * 4 * 4 = 64 cubic decimeters
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This is the first correct answer. I wish you progress!
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