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The side length of the square is 10 cm. The area of triangle a is 20 cm less than that of triangle B. find the length of line ab
The area of triangle a is 20 square centimeter smaller than that of triangle B. according to the figure, the area of triangle DCB is 20 square centimeter larger than that of square CDEA, so the area of triangle DCB is 10 × 10 + 20 = 100 + 20 = 120 (square centimeter). Because the side length of square CD = 10 centimeter, the length of CB is 120 × 2 △ 10 = 24 (centimeter), so the length of AB is 24-10 = 14 A: the length of AB is 14cm
It is known that the side length of the square in the figure below is 5cm, and the shadow part a is 5.4cm larger than the shadow part B. how large is the area of the triangle ABC?
5 × 5 = 25 cm
25 + 5.4 = 30.4 square centimeter
The area of a triangle is 50 square centimeters, the height is 25 centimeters, how many centimeters is the bottom?
The bottom is: 50 × 2 / 25 = 100 / 25 = 4cm
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