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Given the system of equations ax + 2Y = 8,3x + 6y = B, when a and B are values, the system of secondary equations has no solution
First solve the equation,
x=(24-b)/(3a-3),
y=(24-ab)/(6-6a),
When a = 1,
The equation is 3x + 6y = 24,3x + 6y = B,
When B ≠ 24, the equation has no solution
Therefore, when a = 1, B ≠ 24, there is no solution
1. When a___ When a + 2Y = 1, there is a unique solution 3x + y = 2___ The equations ax + 2
1. When a___ The equation AX + 2Y = 1 has a unique solution
3x+y=2
2. When a___ The equation AX + 2Y = 1 has no solution
3x+y=3
3. When m___ When x + 2Y = 1, there are infinite solutions
2x+my=2
Write the question number,
1、4
2、3
3、4
Sincerely answer for the best
If the equations {3x-2y = 4 ax + 2Y = B, then a_________________________________ The system of equations has a set of solutions
A is not equal to - 3
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