6 = 1 + 2 + 3, so 6 is perfect. About 2200 years ago, Euclidean pointed out that the N-1 power of 2 is prime, so the N-1 power of 2 * (the N-1 power of 2) is a perfect number. Please write the next perfect number after 6 according to this conclusion. Why?

6 = 1 + 2 + 3, so 6 is perfect. About 2200 years ago, Euclidean pointed out that the N-1 power of 2 is prime, so the N-1 power of 2 * (the N-1 power of 2) is a perfect number. Please write the next perfect number after 6 according to this conclusion. Why?

n=3
2 & # 179; - 1 = 7 is prime
Then the (3-1) power of 2 × (2 & # 179; - 1)
=4×7
=28

What is the m power of 2 plus the m power of 2 minus the m power of 3 * 2 plus the 1 power

A:
M power of 2 plus m power of 2 minus m power of 3 * 2 plus 1 power
2^m+2^m-3*2^(m+1)
=2*2^m-3*2*2^m
=2*2^m-6*2^m
=-4^2^m
=-2^(m+2)

Whether there is p and Q to make x ^ 2-px + Q divisible by x ^ 2 + 2x + 5, if there is, find out the value of P and Q, otherwise explain the reason
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The first one is not x ^ 4. If it is, it is on Baidu

The first one is x ＾ 4-px ^ 2 + QP = 6, q = 25, assuming that there exists, because the fourth power coefficient is 1, another factor can be set to be (x ^ 2 + ax + b), so (x ^ 2 + ax + b) (x ＾ 2 + 2x + 5) = x ＾ 4 + PX ^ 2 + Q, expanding on the left side, we can get: x ^ 4 + (a + 2) x ^ 3 + (5 + 2A + b) x ^ 2 + (5a + 2b) x + 5B = x ^ 4 + PX ^ 2 + Q comparison coefficient, X