Given that one part of X + X is equal to 3, find the square of (one part of x-x),

Given that one part of X + X is equal to 3, find the square of (one part of x-x),

x+1/x=3
Two sides square
x²+2+1/x²=9
x²+1/x²=7
x²-2+1/x²=7-2=5
(x-1/x)²=5

The square of three x equals two. What is x? Find two values of X
Is the square of x minus five and x plus two equal to zero? Finding two values of X

3x²=2x
That is, X (3x-2) = 0
So x = 0 or 3 / 2

The square of x minus x is equal to 1

x²-x+1/4=1+1/4=5/4
(x-1/2)²=(±√5/2)²
x-1/2=±√5/2
x=(1-√5)/2,x=(1+√5)/2

Given that X-Y equals 3 and X * y equals 4, find the square of x plus the square of Y

X square + y square
=X square - 2XY + y square + 2XY
=(X-Y) square + 2XY
=3*3+2*4
=17

It is known that the square of the sum of X + y is equal to 4, and the square of the sum of X-Y is equal to 3
It is known that the square of the sum of X + y is equal to 4, and the square of the sum of X-Y is equal to 3

1. X square + y square + 2XY = 4
X square + y square - 2XY = 3
We get x square + y square = 7 / 2
XY=-1/4

3 square -- 2 "x + 3" square -- X_ 9》=81

This is to solve the equation
3(x+5)^2-2(x+3)^2-(x-9)(x+9)=81
3(x^2+10x+25)-2(x^2+6x+9)-x^2+81=81
3x^2+30x+75-2x^2-12x-18-x^2=0
18x+57=0
x=-19/6

The square of X-9 / 5 and the square of x-25 / 9-x are reciprocal to each other. Find the value of X
The sooner the better. Thank you for solving this problem
Correct that; the square of 9-x

Reciprocal is the transposition of numerator and denominator
x-5=x^2-25
x^2-9=（9-x）^2
Solve the second equation and get x = 5

Given that the square of x-3 = 0, find the square of the algebraic formula x (x + 1) - X-9

Because X & # 178; - 3 = 0
So x & # 178; = 3
x(x + 1)² - x(x² + x) - x - 9
= x(x + 1)(x + 1) - x²(x + 1) - x - 9
= x(x + 1) - x - 9
= x² - 9
= 3 -9
= -6
If you don't understand, you are welcome to ask,

The square of 4 (x plus 1) is 25. What is x?

That is, (x + 1) ² = 25 / 4
x+1=-5/2,x+1=5/2
x=-7/2,x=3/2

The square of (7-x) plus the square of x equals 25

From (7-x) & sup2; + X & sup2; = 25
49-14x+x²+x²-25=0,
2x²-14x+24=0,
x²-7x+12=0,
（x-4）（x-3)=0,
∴x1=4,x2=3.
This is the content of quadratic equation of one variable