On the value of 10 ^ 2x-3y given 10 ^ x = 3 10 ^ y = 2

On the value of 10 ^ 2x-3y given 10 ^ x = 3 10 ^ y = 2

10^2x-3y
=10^2x÷10^3y
=(10^x)^2÷(10^y)^3
=3^2÷2^3
=9/8

First simplify, then evaluate: x2 − y2x + Y-2 (x + y), where x = 3, y = - 13

The original formula = (x + y) (x − y) x + Y-2 (x + y) = x-y-2x-2y = - x-3y, when x = 3, y = - 13, the original formula = - 3-3 × (- 13) = - 2

First simplify and then evaluate (x2-4 / x2-4x + 4 - X-2 / x + 2) △ X / X-2, where x = 2 √ 3-2

[(X^2-4)/(X^2-4X+4)-(X-2)/(X+2)]÷[X/(X-2)]=[(x-2)(x+2)/(x-2)^2-(x-2)/(x+2)]×(x-2)/x=[(x+2)/(x-2)-(x-2)/(x+2)]×(x-2)/x={[(x+2)^2-(x-2)^2/[(x-2)(x+2)]}×(x-2)/x=8x/[(x-2)(x+2)]}×(x-2)/x=8/(x+2)=8/(2...