Solve the equation 4 / X-8 / x + 2 = 1, remove the denominator, get () and get ()

Solve the equation 4 / X-8 / x + 2 = 1, remove the denominator, get () and get ()

Solve the equation 4 / X-8 / x + 2 = 1, remove the denominator, get (2x-x + 16 = 8), solve (x = - 8)

When solving the equation (x + 1 of 4) - 2x + 1 of 3) = 1, the correct way to remove the denominator is ()
A.3x＋1－8x－1＝1 B.3(x＋1)－4(2x＋1)＝1
C.3x＋3－8x＋4＝12 D.3(x＋1)－4(2x＋1)＝12

Multiply 12 on both sides
 
3（x+1）-4（2x+1）=12
 
Select D
 

In solving the equation of three (x + 1) - six (x-1), to the denominator of 2 (x + 1) - (x-1) = 1, the reason for his mistakes is that

It's the one on the right. I forgot to multiply it by six