In order to prepare for Xiaoming's college tuition of 20000 yuan, his parents took part in the education savings when he was in the seventh grade. They prepared to save a part of the money first, and then borrow a part of the money when he was in the University. Xiaoming's parents saved a six-year loan with an annual interest rate of 2.88%, and the loan when he was in the University was to be paid off in 10 years, with an annual interest rate of 6.21%, 50% of the loan interest is subsidized by the government. If the interest obtained from participating in the education savings is equal to the interest indicated in the application for the loan, how much money did Xiao Ming's parents spend to participate in the education savings? How much money are they going to make? (there is no interest tax on education savings)

In order to prepare for Xiaoming's college tuition of 20000 yuan, his parents took part in the education savings when he was in the seventh grade. They prepared to save a part of the money first, and then borrow a part of the money when he was in the University. Xiaoming's parents saved a six-year loan with an annual interest rate of 2.88%, and the loan when he was in the University was to be paid off in 10 years, with an annual interest rate of 6.21%, 50% of the loan interest is subsidized by the government. If the interest obtained from participating in the education savings is equal to the interest indicated in the application for the loan, how much money did Xiao Ming's parents spend to participate in the education savings? How much money are they going to make? (there is no interest tax on education savings)


If the loan is x yuan, the education savings will be (20000-x) yuan
6(20000-x)*2.88%=10*6.21%*x/2
The solution is x = 7150.8
12849.2 yuan was used to participate in education savings and 7150.8 yuan was prepared for loan



x+3/7x=1/2+2/3


x+3/7x=1/2+2/3
10/7x=3/6+4/6
10/7x=7/6
x=7/6*7/10
x=49/60



A junior high school mathematics problem, with the equation solution
A train has been delayed for six minutes, from 40 kilometers per hour to 60 kilometers per hour. How many kilometers can we make up for the delay?
Column equivalent relations, trouble process to say clearly, and, the requirement is "how many kilometers to walk like this", had better not set the time, get rid of, this is today's mathematics homework, trouble faster!!!


Let x hours make up, 6 minutes = 0.1 hours, (0.1 + x) * 40 = 60x, x = 0.2 hours, that is 12 minutes



Solution equation: 2x ^ 3 + 2, x ^ 2-7x + 7, x + 2 = 0


Is it 2x & # 178; + 2 / X & # 178; - 7x + 7 / x + 2 = 02 (X & # 178; - 2 + 1 / X & # 178;) - 7 (x-1 / x) + 6 = 02 (x-1 / x) &# 178; - 7 (X-1 / x) + 6 = 0 if not clear, use the substitution [2 (x-1 / x) - 3] [(x-1 / x) - 2] = 02 (x-1 / x) - 3 = 0 X-1 / X-2 = x = - 1 / 2 x = 2 x = 1 + √ 2 x = 1 - √ 2 to test the equation



7x-5x = 20, then what is x equal to


I'm the latest:
7x-5x=20
2x=20
2x÷2=20÷2
x=10



3.5x + 4.7x = 24.6 find x equal to


3.5X+4.7X=24.6
8.2x=24.6
x=3



7x = 5x + 3 minus x-3 on both sides equals?
Please write down the process


7x = 5x + 3 minus X-2 on both sides
7x-(x-3)=5x+3-(x-3)
7x-x+3=5x+3-x+3
6x+3=4x+6
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The square of (7x + 5x) - (7x-10) is equal to () * ()


Using the formula A ^ 2-B ^ 2 = (a + b) (a-b)
So (7x + 5x) ^ 2 - (7x-10) ^ 2 = [(7x + 5x) - (7x-10)] [(7x + 5x) + (7x-10)] = (5x + 10) (19x-10)



What is 7x + 3-5X after simplification


Equal to 2x + 3



x^3-5x^2+7x-3


x^3-5x^2+7x-3
=x³-3x²-(2x²-7x+3)
=x²(x-3)-(2x-1)(x-3)
=(x-3)[x²-(2x-1)]
=(x-3)(x²-2x+1)
=(x-3)(x-1)²