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For the rational number a, B (a + B is not equal to 0) defines the operation "*" as follows: a * b = a + 1 / B, for example, 1 * 2 = 1 + 1 / 2 = 3 / 2, - 2 * 5 = - 2 + 1 / 5 = - 9 / 5 Following the above, calculate the following formulas (1) 2 * 3; (2) 1 * (2 * 3) to find the process and answer
（1）2*3=2+1/3 = 7/3（2）1*（2*3）=1*(7/3)=1+1/(7/3)=1+3/7=10/7
Solving logarithmic inequality (3a-1) x + 5A > loga ^ x
X is less than 5 / (1-3a + loga)
Log a is the logarithm of base B = log B is the logarithm of base a, (a > 0, b > 0, a is not equal to B, a and B are not equal to 1), then AB =?
log(a)b=log(b)a
Bottom changing formula
lgb/lga=lga/lgb
(lgb)^2=(lga)^2
(lgb-lga)(lgb+lga)=0
Because a ≠ B
So LGA ≠ LGB
lga+lgb=0
lg(ab)=0
ab=1
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