If one side of the rectangle is a-2b, and the other side is 2a and B larger than the first side, the perimeter of the rectangle is a-2b_______ I'm in a hurry!

If one side of the rectangle is a-2b, and the other side is 2a and B larger than the first side, the perimeter of the rectangle is a-2b_______ I'm in a hurry!


If one side of the rectangle is a-2b, and the other side is 2A larger than the first side plus B, the perimeter of the rectangle is 8a-6b
The other side is a-2b + 2A + B = 3a-b
The perimeter of the rectangle is 2 × (a-2b + 3a-b) = 8a-6b



If one side of the rectangle is a-2b, and the other side is 2A + B larger than the first side, the perimeter of the rectangle is a-2b______ .


The other side is 2A + B + a-2b = 3a-b. therefore, the perimeter of the rectangle is 2 [a-2b + 3a-b] = 8a-6b



The side length of a rectangle is 2A + B, and the other side is longer than it?
Hurry up, or you'll die!


2(2a+b+a-b+2a+b)
=10a+2b