[3b-2] & sup2; + | 2a-b-3 | = 0, what are the values of A.B | Math enthusiast | Mathematical art

[3b-2] & sup2; + | 2a-b-3 | = 0, what are the values of A.B

Remember that the absolute value of the sum of squares is nonnegative
If their sum is 0, then they are 0
So it's Suez
3B-2=0
B=2/3
2A-B-3=0
2A-2/3-3=0
2A=11/3
A=11/6

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