If LA + 2L + LB + 3L = 0, then 3A + 2B=

If LA + 2L + LB + 3L = 0, then 3A + 2B=

If the sum of absolute values of quantities is 0, the absolute values of quantities are respectively equal to 0
a+2=0
b+3=0
∴a=-2 b=-3
3a+2b=-12

If LAL = 3, LBL = 13. La + 3L + lb-2l = 0, when a and B have the same sign, a + B =, when a and B have different signs, a * b =. The title is a little difficult

Because | a + 3 | + | B-2 | = 0,
|a+3|≥0,|b-2|≥0,
So a + 3 = 0, B-2 = 0,
So a = - 3, B = 2

Given that the real number a satisfies | 2006-a | + a − 2007 = a, then a-20062=______ ．

According to the meaning of the question, A-2007 ≥ 0, the solution is a ≥ 2007, the original formula can be changed into: a-2006 + a − 2007 = a, that is, a − 2007 = 2006, two sides of the square, A-2007 = 20062, a-20062 = 2007

La BL + LB + 5L = 0, then a = () B & # 178; = ()
L-al = l-5l, then a = ()
The product of all integers whose absolute value is greater than 2 and not greater than 3.4 is ()
There is a set of numbers, 1, 2, 5, 10, 17, 26 Then the 10th number is (), and the 50th number is ()
If a, B are opposite to each other, C and D are reciprocal, LXL = 3, then x & # 178; + (a + B + CD) x = ()
If a and#10048; b = a and#178; + b-ab, then (- 3) & #10048; 4 = ()

If LA BL + LB + 5L = 0, then a = - 5) B & # 178; = (25)
/- Al = l-5l, then a = (± 5)
The product of all integers whose absolute value is greater than 2 and not greater than 3.4 is (- 9)
There is a set of numbers, 1, 2, 5, 10, 17, 26 Then the 10th number is (82), and the 50th number is (49 & # 178; + 1 = 2042)
If the reciprocal is CD + D, then it is opposite to each other
If a and#10048; b = a and#178; + b-ab, then (- 3) & #10048; 4 = (25)