When k is what value, the solution of the equation 2x + K / 3 + 1 = 1-x / 2 + k is equal to 1?

When k is what value, the solution of the equation 2x + K / 3 + 1 = 1-x / 2 + k is equal to 1?

The solution of 2x + K / 3 + 1 = 1-x / 2 + k is equal to 1
2*1+k/3+1=1—1/2+k
3+k/3=1/2+k
k=15/4

It is known that the quadratic power of la-1l and (b-2) are opposite to each other. Calculate (a + 2) (B + 3) / 1 + (a + 4) (B + 5) / 1 + (a + b) (B + 7) +
+(a + 2004) (B + 2005)

If la-1l is greater than or equal to 0, (b-2) & sup2; greater than or equal to 0, how can they be opposite numbers
If there is no mistake, the only possibility is a = 1, B = 2
The formula you want to calculate is also wrong. According to the title, you can't find the rule in the ellipsis

If the squares of La + B + 1L and (a-b + 1) are opposite to each other, then the relationship between a and B is a

The squares of La + B + 1L and (a-b + 1) are opposite to each other
So La + B + 1L + (a-b + 1) ^ 2 = 0
The sum of absolute value and square is greater than or equal to 0, and the sum is equal to 0. If one is greater than 0, then the other is less than 0
So both are equal to zero
So a + B + 1 = 0, A-B + 1 = 0
a-b+1=0
b=a+1
b-a=1>0
So b > a

What is the value of B if the line L passes two points (- 1,1) (2,5) and the point (1006, b) is on l

Let l be y = KX + a
X = - 1, y = 1, x = 2, y = 5
﹛1=-k+a
5=2k+a
The solution is k = 4 / 3, a = 7 / 3
∴y=4x/3+7/3
X = 1006, y = b
b=1006×4／3+7/3=4031/3

The results of (1 + 2 + 5 + L + 2011) - (2 + 4 + 6 + L + 2010) are as follows: () a.1004 b.1006 c.1008 d.1010 which one to choose? Why

In the front brackets, it should be (1 + 3 + 5 + L + 2011). (1 + 3 + 5 + L + 2011) - (2 + 4 + 6 + L + 2010) = (1-2) + (3-4) + (5-6) + L + (2009-2010) + 2011

The general equation of a straight line l can be obtained by the cosine value cos α = - 3 / 5 of the inclination angle α of P (- 1,2)

cos²α+sin²α=1
So sin α = 4 / 5
So k = Tan α = - 4 / 3
So Y-2 = - 4 / 3 (x + 1)
So 4x + 3y-2 = 0

If the line L passes through points a (- 1,2), B (2,5), then the inclination angle of the line L is? And the slope is?
Because there were no books, I didn't understand in class

K = (5-2) / (2 + 1) = 1, and the inclination angle is 45 degrees

Given that two points a (- 1, - 5) B (3, - 2) line L passes through point (1,1) and the inclination angle is twice that of line AB, then the equation of the line is?

Linear equation: y = 24 / 7x-17 / 7

It is known that the inclination angle of the straight line L of two points a (- 1, - 5) B (3, - 2) is half of that of the straight line AB, and it passes through the points (1,3). The general equation of L is obtained

Let the linear AB equation y = ax + B and the linear l equation y = CX + D
-5=-a+b
-2=3a+b
a=3/4,b=-17/4
The inclination angle of line L is half of that of line ab
c=1/3
Line L passing through point (1,3)
3=1*1/3+d
d=8/3
The general equation of L is y = x / 3 + 8 / 3

Given that a straight line L passes through the point P (2, - 1), its inclination angle is α, and a straight line L 'passes through the points a (- 2,3), B (4, - 5), its inclination angle is α', and α = 1 / 2 α ', the equation of L and l' is solved

K (L ') = Tan α' = (3 + 5) / (- 2-4) = - 4 / 3} the equation is Y-3 = (- 4 / 3) (x + 2), that is 4x + 3y-1 = 0 ∵ α = (1 / 2) α '{Tan α' = 2tan α / [1 - (Tan α) ^ 2]} (- 4 / 3) [1 - (Tan α) ^ 2] = 2tan α} - 2 [1 - (Tan α) ^ 2] = 3tan α} 2 (Tan α) ^ 2-3tan α - 2 = 0, that is (Tan α - 2)}