Finding limit limx-0 sin3x / sin5x
Limx-0 sin3x / sin5x = limx-0 [(sin3x / 3x) * 3x] / [(sin5x / 5x) / 5x] = limx-0 [(sin3x / 3x) * 3x] / [(sin5x / 5x) / 5x] = 3 / 5limx-0 [(sin3x / 3x) / (sin5x / 5x)] = 3 / 5 [limx-0 (sin3x / 3x)] / [limx-0 (sin5x / 5x)] = 3 / 5 * 1 / 2 = 3 / 5. I hope I can help you solve this problem
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