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The sum of three continuous natural numbers is 36. These three natural numbers are (), (), (), and their product is ()?
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36÷3=12
These three numbers are 11, 12 and 13
Their product is 11 × 12 × 13 = 1716
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If the product of three continuous natural numbers is 366, what is the sum of them
The product of these three numbers is not 366. Is this problem wrong?
21, what else can I do? I'll try it directly! That's 6.7.8. This kind of problem can only be tested!
Divide 19 into the sum of n natural numbers, how to make its product maximum
19=2+2+3+3+3+3+3
2*2*3*3*3*3*3=972
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