The product of two numbers is 60. If one factor is divided by 3 and the other factor is divided by 4, what is the product?

The product of two numbers is 60. If one factor is divided by 3 and the other factor is divided by 4, what is the product?

60÷3÷4 = 20÷4 = 5
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How many consecutive zero processes are there when 1 times 2 times 3 times 4 times 5 times 6 times 7 times 8 times 9 times 100 in turn

Multiply several numbers to find out how many continuous zeros there are at the end of the product. Just find out the number of factors 2 and 5 in the product, and the less number of factors is the number of continuous zeros at the end of the product
It's obvious that when 1 times 2 times 3 times 4 times 5 times 6 times 7 times 8 times 9 times 100 times, the factor of 5 is less
therefore
There are 24 factors with a factor of 5
So there should be 24 consecutive zeros

The product of two numbers is 60. If one number is multiplied by 5 and the other number is divided by 4, what is the product

The product becomes 60 × 5 △ 4 = 75