Given x + y = 5, x ^ 2 + y ^ 2 = 7, find the value of XY. Given x + y = 4, xy = 3, find the value of x ^ 2 + y ^ 2
1. Because x + y = 5, x ^ 2 + y ^ 2 = 7, so (x + y) ^ 2 = 25 = x ^ 2 + y ^ 2 + 2XY = 7 + 2XY, xy = 9 2. Because x + y = 4, xy = 3, so (x + y) ^ 2 = 16 = x ^ 2 + y ^ 2 + 2XY = x ^ 2 + y ^ 2 + 6, so x ^ 2 + y ^ 2 = 10
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