Given that 0 is less than X and less than or equal to 1 / 4, find the maximum value of the function f (x) = (x2-2x + 2) / x?

Given that 0 is less than X and less than or equal to 1 / 4, find the maximum value of the function f (x) = (x2-2x + 2) / x?

f(x)=(x^2-2x+2)/x,x∈(0,1/4]
Order 0

Given the function f (x-1) = x2-2x (x is greater than or equal to 1), find f (x)

F(X-1)=x^2-2x=(x-1)^2-1
x>=1 x-1>=0
Let X-1 = t
F(t)=t^2-1 t>=0
F(x)=x^2-1 x>=0

If we know that the function y = f (x) is an odd function on R, and if x is greater than or equal to 0, f (x) = x2-2x, then f (- 1) =? Question 2
Question 1: if the function y = f (x) is known to be odd on R, and if x is greater than or equal to 0, f (x) = x2-2x, then f (- 1) =? Question 2: let the image of function y = f (x) and function g (x) be symmetric with respect to x = 3, then the expression of G (x) is? Question 3: if the sum of all odd terms in the expansion of (x + root x) ^ n is equal to 512, then the middle term of the expansion is?

1. This is a piecewise function; first, when x > 0, f (x) = x ^ 2-2x + 1; then solve X