Take the square of 9 (a + 1) square (A-1) - 6 (A's Square-1) (B's Square-1) + (B + 1) square (B-1) square factorization factor

Take the square of 9 (a + 1) square (A-1) - 6 (A's Square-1) (B's Square-1) + (B + 1) square (B-1) square factorization factor

The square of the square of 9 (a + 1) - 6 (the square of A-1) (the square of B-1) + the square of the square of (B-1) = 9 (a + 1) & sup2; (A-1) & sup2; - 6 (A & sup2; - 1) (b & sup2; - 1) + (B + 1) & sup2; (B-1) & sup2; = 3 & sup2; (a + 1) & sup2; (A-1) & sup2; - 2 * 3 (a + 1) (A-1) * (...)

2.7x=3（x-12）

2.7X=3X-36
36=0.3X
X=120

M square - 4m ≤ 0, what is the solution!

Let m ^ 2-4m = 0, and use the formula method to get m = 0 or 4. Combined with the image of quadratic function, we can know that when m is greater than or equal to 0 and less than or equal to 4, the original inequality is satisfied, so the solution is m greater than or equal to 0 and less than or equal to 4