In a proportional formula, the sum of the two external terms is 37, the difference is 13, and the ratio of the two ratios is 5 / 6?

In a proportional formula, the sum of the two external terms is 37, the difference is 13, and the ratio of the two ratios is 5 / 6?

(37+13)÷2=25
37-25=12
The external terms are 25 and 12
The ratio is 5 / 6
So it can be 12:14.4 = 125 / 6:25 or 25:30 = 10:12

For a formula, the sum of the two external terms is 37, and the difference is 13. The ratio of the two ratios is 56______ ．

Let this ratio be: A: B = C: D, then a + D = 37, A-D = 13, a = (37 + 13) △ 2 = 25, d = 37-25 = 12. Because: A: B = 56, B = 25 △ 56 = 30, C: D = 56, C = 12 × 56 = 10, this ratio can be: 25:30 = 10:12. So the answer is: 25:30 = 10:12

For a formula, the sum of two external terms is 38, the difference is 22, and the ratio of the two ratios is 8 / 5

The larger one is (38 + 22) △ 2 = 30, and the smaller one is 38-30 = 8
The ratio is 8:5 = 48:30
It's not unique