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The distance between a, B and C is 300 meters in turn. A, B and C walk 100 meters, 90 meters and 85 meters in turn every minute. If a, B and C start at the same time, it will take a few minutes The distance between a, B and C is 300 meters in turn. A, B and C walk 100 meters, 90 meters and 75 meters in turn every minute. If a, B and C start at the same time, the distance between a and B is equal for the first time in a few minutes
Suppose that after X minutes, the distance between a and B, C is equal for the first time
300×2-(100-85)x=(100-90)x-300,
600-15x=10x-300,
25x=900,
x=36;
A: after 36 minutes, the distance between a and B, C is equal for the first time
So the answer is: 36
C is in the front, a is in the back, and B is in the middle, 300 meters apart. A, B, and C walk 100 meters, 50 meters, and 85 meters per minute respectively. If the three start in the same direction at the same time, how many minutes later will a be the same distance from B and C for the first time?
If the distance between a and B is equal for the first time, then it must be that after a overtakes B, when the distance between B and C is equal for X minutes, the distance between a and C is 600 - (100-85) x, and the distance between a and B is (100-50) x-300, so 600 - (100-85) x = (100-50) x-300 gets 600-15x = 50x-300 x = 180 / 13, that is, after 180 / 1
The distance between a, B and C is 500 meters in turn. A, B and C walk 100 meters, 90 meters and 75 meters per minute in turn. If a, B and C start at the same time, then after () minutes, the distance between a and B is equal for the first time
First of all, the speed difference between B and C is 90-75 = 15, and the speed difference between a and B is 100-90 = 10, so B catches up with C first. Then the distance between a and B is equal for the first time,
500 / (90-75) = 100 / 3 = (33 + 1 / 3) points
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