1. CP and BP divide ∠ DCA and ∠ abd equally, and try to explain: ∠ P = 1 / 2 (∠ a + ∠ d) 2. In △ ABC, ab = AC, the center line BD on the side of AC divides the perimeter of △ ABC into two parts, 12cm and 15cm, and calculates the length of each side of the triangle 3. In △ ABC, a = ACB, CD is the bisector of ACB, CE ⊥ AB is e (1) Try to explain ∠ CDB = 3 ∠ DCB (2) If ∠ DCE = 48 °, calculate the degree of ∠ ACB 4. In RT △ ABC, ∠ ACB = 90 °, CD is the height on the edge of AB, ab = 13cm, BC = 12cm, AC = 5cm, and find the length of CD 5. In the quadrilateral ABCD, e and F are the midpoint of AD and BC respectively. Given that the area of quadrilateral ABCD is 1, calculate the area of quadrilateral debf There's no way to make a picture. I also want to have a picture, so you can do it. Oh, and, 》OK, I'll try to wait at 8:20.

1. CP and BP divide ∠ DCA and ∠ abd equally, and try to explain: ∠ P = 1 / 2 (∠ a + ∠ d) 2. In △ ABC, ab = AC, the center line BD on the side of AC divides the perimeter of △ ABC into two parts, 12cm and 15cm, and calculates the length of each side of the triangle 3. In △ ABC, a = ACB, CD is the bisector of ACB, CE ⊥ AB is e (1) Try to explain ∠ CDB = 3 ∠ DCB (2) If ∠ DCE = 48 °, calculate the degree of ∠ ACB 4. In RT △ ABC, ∠ ACB = 90 °, CD is the height on the edge of AB, ab = 13cm, BC = 12cm, AC = 5cm, and find the length of CD 5. In the quadrilateral ABCD, e and F are the midpoint of AD and BC respectively. Given that the area of quadrilateral ABCD is 1, calculate the area of quadrilateral debf There's no way to make a picture. I also want to have a picture, so you can do it. Oh, and, 》OK, I'll try to wait at 8:20.

Don't you have a picture? I'm dizzy if I don't see it! Maybe I'll do it with a picture! Question 4: ∵ △ ABC is RT △ s △ ABC = 5 × 12 △ 2 = 30, with BC as the base, let CD be x ∵ 13 × x = 60 ∵ x = 60 ∵ 13 x = 60 / 13, I'll try my best! Question 3: ∵ △ ABC is isosceles ∵ three lines in one

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1. The whole class went to visit the Municipal Science and Technology Museum, which is 25 kilometers away from the school. The boys rode an hour and 20 minutes ahead of time, while the girls took a car and arrived at the same time. The speed of the girls is three times that of the boys
2. We are going to use 80hm2 area to grow vegetables, the work efficiency is 1.5 times higher than the original cost, and the project is completed 20 days ahead of schedule
3. If the square of x minus the square of 4xy + 4Y = 0, then x + y is X-Y=
4. If half x = three y, then the square of X - 2XY + 3Y the square of 7x the square of Y=
5. If the tap water does not exceed 5 tons, it will cost 1.5 yuan per cubic meter. If it exceeds 5 tons, it will be charged according to a certain amount. Party A pays 17.5 yuan and Party B pays 27.5 yuan. The water quantity of Party A is two-thirds of that of Party B. find out how much yuan per cubic meter if it exceeds 5 tons. (fractional equation)
6. There are two ways. It takes 1.2 million yuan for Party A and Party B to work together for 24 days. If the two teams work together for 20 days, the rest of team B will work for 20 days, which will cost 1.1 million yuan. Q: how many days does it take for Party A and Party B to work alone? How many million yuan does it take to work alone?
We need a formula

1: Set the speed of boys as X 80 + 25 / 3x = 25 / x x x = 5 / 24 3x = 5 / 8 (female) 2: set the original plan as X 80 / x = 80 / 1.5x + 20 x = 4 / 3 every day

I'll get it
3. It is known that the solution of the equation A-X / 2 = bx-3 / 3 is = 2, where ≠ 0 and B ≠ 0
2. Solve the following equation about:
⑴6x+3(m-x)=13 ⑵5x-3=nx+7 (n≠5)

3. It is known that the solution of the equation A-X / 2 = bx-3 / 3 is = 2, where ≠ 0 and B ≠ 0
Substituting x = 2 into the equation, A-1 = 2b-1, a-2b = 0
2. Solve the following equation about:
⑴、6x+3(m-x)=13
6x+3m-3x=13
3x=13-3m
x=13/3-m
⑵、5x-3=nx+7 (n≠5)
5x-nx=7+3
(5-n)x=10
x=10/(5-n)