But according to Archimedes' principle, f floating = PGV row, Does the water surface rise? If there is no buoyancy, there is no v-row,

But according to Archimedes' principle, f floating = PGV row, Does the water surface rise? If there is no buoyancy, there is no v-row,

The water surface will rise, because the bridge pier pushes the water out of the water and takes up part of the water volume. But it is wrong to say that there is no buoyancy or V row
You need to understand the cause of buoyancy. Buoyancy is caused by the pressure difference between the upper and lower surfaces. If you learn pressure, you will know that for the same liquid, the greater the depth, the greater the pressure. Therefore, the pressure on the upper surface of the object is less than that on the lower surface. This pressure is generated by water
The pressure acts on the area and produces pressure. Therefore, the force on the lower surface will be larger and the object will be dragged up. If it is completely closed, there will be no water below. How can we pull up the object? Naturally, there will be no buoyancy
Archimedes principle is actually produced under this premise. Without the pressure difference between the upper and lower surfaces, the concept of buoyancy will not exist at all. What about Archimedes principle?
I hope I can help you

Buoyancy experiment (Archimedes principle)
Here is a solid aluminum block, a spring dynamometer, a density meter and a cup of oil to be measured. Please use Archimedes principle to measure the density of oil. Briefly write down your experimental steps and calculation formula?

The problem should be to find the density of solid aluminum block
The mass M1 in air and the mass m2 in oil of the solid aluminum block are respectively weighed by the spring dynamometer
Measure the density P1 of oil with density meter
Buoyancy of solid aluminum block f = volume of solid aluminum block V × density of oil p = m1-m2
v=(m1-m2)/P1
Solid aluminum density P2 = M1 / V
The unit of measurement should be consistent in the experiment

Buoyancy exercises
The ice in the beaker floats in the water, the upper part of the ice is higher than the mouth of the beaker, and the water surface in the beaker is just level with the mouth of the beaker. Conclusion: the water surface is always level with the mouth of the beaker during the melting process of the ice
Q: please compare the volume of water formed by ice with the volume of boiled water from ice rafts to draw the above conclusion. Please prove it

When the ice is floating, let the volume of the underwater part be V1, and the volume of the water part be v2. Because of the floating, Mg = f floats, that is, P ice (V1 + V2) g = P water GV row. In fact, V row is V1. The expression just now is not only the balance of two forces, but also the formula that ice changes into water, that is, m ice = m water, that is, P ice (V1 + V2) = P water V water. It can be seen that V water is the V row just now, that is V1. Therefore, after the ice changes into water, The volume of water is just the volume of ice under water, so the overall water level will not rise