There is a 2-meter-long cylindrical steel. If it is cut into four small cylinders, the sum of the surface area of these four small cylinders will increase by 56.52 square centimeters. What is the volume of this cylindrical steel______ Cubic centimeter

There is a 2-meter-long cylindrical steel. If it is cut into four small cylinders, the sum of the surface area of these four small cylinders will increase by 56.52 square centimeters. What is the volume of this cylindrical steel______ Cubic centimeter

2 m = 200 cm, 56.52 ± [(4-1) × 2] × 200 = 56.52 ± [3 × 2] × 200, = 56.52 ± [6 × 200, = 1884 (cubic centimeter); answer: the volume of this cylinder is 1884 cubic centimeter. So the answer is: 1884

There is a 2-meter-long cylindrical steel. If it is cut into four small cylinders, the sum of the surface area of these four small cylinders will increase by 56.52 square centimeters. What is the volume of this cylindrical steel______ Cubic centimeter

2 m = 200 cm, 56.52 ± [(4-1) × 2] × 200 = 56.52 ± [3 × 2] × 200, = 56.52 ± [6 × 200, = 1884 (cubic centimeter); answer: the volume of this cylinder is 1884 cubic centimeter. So the answer is: 1884

After a 2m steel is cut into two small columns of the same size, the surface area increases by 56.52. What is the original surface area of this steel?

The increased surface area is the area of the cross section, that is, the area of two bottom surfaces. The area of one bottom surface is 56.52/2 = 28.26 square meters
Bottom area = 28.26, square of bottom radius = 28.26 / 3.14 = 9, radius = 3, diameter = 6,
Perimeter of bottom surface = 3.14 * 6 = 18.84 square meters,
Side area = 18.84 * 2 = 37.68 m2,
Surface area = two bottom areas + side area = 56.52 + 37.68 = 94.20 square meters