How to solve the equation 2 / 3x + 60 + x = 160?

How to solve the equation 2 / 3x + 60 + x = 160?


2/3x+60+X=160
(2/3+1)x=160-60
5/3x=100
x=100÷5/3
x=60



Solving equation 3x + 2 (23-x) = 60


3x+2(23-x)=60
3x+46-2x=60
x+46=60
x=60-46
x=14



3x ^ 2 + (- 2 / 3x + 3 / 2Y), where x = - 1 / 3, y = 2 / 3
Multiplication and division of integers
First simplify the integral and then evaluate it


When x = - 1 / 3, y = 2 / 3
3x^+[（-3/2)x+(1/3)y^]（2x-2y/3）
=1/3+（1/2+4/27）（-2/3-4/9）
=1/3+（35/54）（-10/9）
=1/3-175/243
=-94/243.

Elden Ring Premiere

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