The relationship between Q1 and Q2 is () A. Q1 > Q2B. Q1 < q2c. Q1 = q2D

The relationship between Q1 and Q2 is () A. Q1 > Q2B. Q1 < q2c. Q1 = q2D

Because a certain amount of hydrogen is fully burned under the same conditions, and water is generated after combustion. If gaseous water is generated, the heat is the same, but the fact is that hydrogen combustion generates liquid water and gaseous water respectively, and heat is also released when gaseous water is converted into liquid water, so Q1 < Q2

Why does the same amount of hydrogen burn in enough oxygen to generate water vapor and give off less heat than liquid water?
I know it's an exothermic reaction, but I think it's endothermic to change from liquid state to gas state. Since it's endothermic, the energy released by liquid state should be less than that released by gas state. What's wrong with my idea?

H2 (g) + 1 ／ 2O2 = H2O (L) △ H1 ＜ 0 ·············· ① H2 (g) + 1 ／ 2O2 = H2O (g) △ H2 ＜ 0 ····················· ② H2O (L) = H2O (g) △ H3 ＞ 0 ····················································································································

Oxygen and hydrogen generate gaseous water and liquid water. Why does liquid water release more heat?
Is the chemical bond of gaseous water different from that of liquid water?

Oxygen reacts with hydrogen to generate gaseous water. Later, gaseous water is transformed into liquid water to release heat. The chemical bonds of gaseous water and liquid water are the same, both are hydrogen oxygen bonds. Liquid water contains hydrogen bonds, which makes water molecules combine more closely