By factoring the algebraic formula X3 + (2a + 1) x2 + (A2 + 2a-1) x + (A2-1), we obtain______ ．

(2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2-2-1) x + (person 2-2-2-1-1-1) x (person 2 + 2 + 2 + 2 + 2-1 + 2-2-2-1) x (2 + 2 + 2 + 2 + 2 + 1 + 2 + 2 + 2 + 2 + 2 + 2-1 + 2 + 2 + 2 + 2 + 2 + 2-1 + 2 + 2 + 2 + 2-1 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2-1 2-1] = (x + 1) (x2 + 2 people x+ Human 2-1) = (x + 1) [(x + human) 2-1] = (x + 1) (x + human + 1) (x + human-1)

-The quadratic factorization of 3ax + 6ab-12ay 9 (a + b) (a-b) - 3 (a-b)

-3ax+6ab-12ay
=-3a(x-2b+4y)
The second power of 9 (a + b) (a-b) - 3 (a-b)
=3(a-b)(3a+3b-3a+3b)
=18b(a-b)

How to divide the factorization of 6ab + 9a-4b-6

（3a-2）（2b+3）

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