The square + 2x - 3 of function y = x has a minimum at point x = ()

The square + 2x - 3 of function y = x has a minimum at point x = ()


The function y = x ^ 2 + 2x-3 can be changed into y = x ^ 2 + 2x + 1-4, that is
y=(x+1)^2-4
So at point x = - 1 there is a minimum of - 4



Finding monotone interval of given function y = x square - 2x-1


Y = x square - 2x-1 = (x-1) ^ 2-2
So when x1, y increases monotonically



Making the function image of y = - x square - 2x + 3


The opening is downward, passing (- 1,4) (- 3,0) (1,0) (0,3)