Draw the graph of function y = 0.5x, and point out the independent variable and its value range

Draw the graph of function y = 0.5x, and point out the independent variable and its value range

When x = 0, y = 0. When x = 2, y = 1. The line passes through points (0, 0), (2, 1), and its image is as shown in the figure. According to the figure, X takes any real number

What is the value range of the independent variable in the function y = X-2 / x ^ 2-5x + 6?
To be specific

Y = X-2 / x ^ 2-5x + 6 x is not equal to 0
Y = X-2 / (x ^ 2-5x + 6) x is not equal to 2 and X is not equal to 3
Y = X-2 / (x ^ 2-5x) + 6, X is not equal to 0 and X is not equal to 5

Both positive scale function and inverse scale function images pass through points (1,4), and the value range of independent variable x above the positive scale function image in the first quadrant
A.X>1 B.0
First of all, I don't understand.

You can draw the picture by yourself. It's clear at a glance

Calculation 2004 / 1949 * 1950 + 2004 / 1950 * 1951 + 2004 / 1951 * 1952 +. + 2004 / 2003 * 2004

According to the original formula of 1 / N (n + 1) = 1 / n-1 / (n + 1) = 2004x (1 / 1949-1 / 1950 + 1 / 1950-1 / 1951 +. + 1 / 2003-1 / 2004) = 2004x (1 / 1949-1 / 2004) = 2004 / 1949-1 = 55 / 1949-1

The second power of 1951 - the second power of 1950 + the second power of 1953 - the second power of 1952 +... + the second power of 2007 - the second power of 2006 =?

1951^2-1950^2＋… ＋2007^2-2006^2 = (1951+1950)(1951-1950)+(1953+1952)(1953-1952)+...+(2007+2006)(2007-2006) =(1950+1951+1952+1953+...+2006+2007) =(1950+2007)*58/2 =114753

How to solve the equation 2x + (99-x) 4 = 254

Equal to 2x + 396-4x = 254
That is 396-254 = 2x
We get x = 71

The detailed solution process of X-2 + X + 2 + X △ 2 + 2x = 99 can not be directly equal to the result,

X（1+1+0.5+2）=99
4.5X=99
X=22

1+x+x^2+x^3+.+x^99+x^100
Same as above, how to calculate? Solve!

This is the summation of the equal ratio sequence. Each term can be regarded as a part, such as A1 = 1, A2 = x A101 = x ^ 100 according to the summation formula of equal ratio sequence, A1 (first term) = 1, last term A101 = x ^ 100, common ratio q = x, n = 101, then Sn = 1 + X + x ^ 2 + x ^ 3 +. + x ^ 99 + x ^ 100 = 1 * (1-x ^ 101) / (1-x) = (1-x ^ 101) / (1-x) = (1-x) / (1-x)

（1+1/2）x（1-1/2)x(1+1/3)x...x(1+1/99)x(1-1/99)=?

(1-1/2)x(1+1/2)x(1-1/3)x(1+1/3)x.x(1-1/99）x(1+1/99)
=1/2x3/2x2/3x3/4x4/3x.x98/99x100/99
=1/2x1x1x.x1x100/99
=50/99

Given X4 + X3 + x2 + X + 1 = 0, find the value of X100 + x99 + x98 + x97 + x96

∵ X4 + X3 + x2 + X + 1 = 0, ∵ X100 + x99 + x98 + x97 + x96 = x96 (x4 + X3 + x2 + X + 1) = 0; so the answer is: 0