The piecewise function f (x) = {x2-x + 1 (x > = 2) x + 1 (x) is known

The piecewise function f (x) = {x2-x + 1 (x > = 2) x + 1 (x) is known

If M = 0 f (x) = - 8x1g (x) = 0, it is obviously a problem. If M 0 is a solution in the range of x = 0 m2, multiply by (2 ^ 1 / 32 + 1) = the original formula (2 ^ 1 / 32 1) and (2 ^ 1 / 32-1) * (2 ^ 1 / 16 + 1) * (2 ^ 1 / 8 1) * (2 ^ 1 / 4 + 1) * (2 ^ 1 / 2 +

We have the following function y = {- x + 2.5 (x)

If you can, take it,
#include
void main()
{
float x;
double y;
Printf ("please enter the value of x)";
scanf("%f",&x);
if(x=4)y=x/2-1.5;
else y=2-1.5*(x-3);
printf("y=%f\n",y);
}

Design program block diagram, calculate the value of 1 * 2 * 3 * 4 *. * n

Change I & gt; 100 in the graph to I & gt; n