Log (2) 9log (3) 4 equals

The answer is: 4

Evaluate; log (8) 9 times the square of log (3) 32-lg5-lg2 + lne=

=lg9/lg8*lg32/lg3-lg5-lg2-lne²
=2lg3/(3lg2)*(5lg2)/lg3-lg5-lg2-lne²
=10/3-1-2
=1/3

LG2 / 1 minus lg5 / 8 plus LG12.5 minus log8 to the 9th power × log27 to the 8th power

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