If 15 is the logarithm of base 5 = m, then 15 is the logarithm of base 3= A m/3 B 1+m C 1-m D m-1

If 15 is the logarithm of base 5 = m, then 15 is the logarithm of base 3= A m/3 B 1+m C 1-m D m-1

Logarithm of base 5 with 15 + logarithm of base 3 with 15
=15 is the logarithm of the bottom 15
=1
If the logarithm of base 5 is m, then the logarithm of base 3 is 1-m

Logarithm of base 4 with 3 * logarithm of base 8 with 4 * logarithm of base 7 with 8 * logarithm of base 7 with M = logarithm of base 9 with 3, then M=
A 27
B18
C 9
D 9/2

Answer c
log(3)4*log(4)8*log(8)7*log(7)m=log(3)m=log(3)9
m=9
log(3)4*log(4)8=log(3)8 log(3)8*log(8)7=log(3)7 log(3)7*log(7)m=log(3)m

loga1=loga2/2+…… Logan / N = n the formula for finding an

loga1 = log(a2*a3*.*an/n!)
a1 = a2*a3*.*an/n!
a1 = a2*a3*.*a(n-1)/(n-1)!
==> 1 = (an/n!)/(a(n-1)/(n-1)!)
==> an = na(n-1)
==> an = a1*n!