Given that {an} is an arithmetic sequence, A3 + a11 = 41, then a6-a7 + A8 is equal to

a6-a7+a8=2a7-a7=a7=(a3+a11)/2=41/2

Given that {an} is an arithmetic sequence and a1-a4-a8-a12 + A15 = 2, then A3 + A13=______ ．

∵ a1-a4-a8-a12 + A15 = 2 ∵ a1 + A15 = A4 + A12 = 2a8 ∵ A8 = - 2 ∵ A3 + A13 = 2a8 = - 4, so the answer is: - 4

Arithmetic sequence a1 + A2 = 40 A3 + A4 = 60 A7 + A8 =?

a1+a2=2a1+d=40
a3+a4=2a1+5d=60
a1=35/2 d=5
a7+a8=2a1+13d=35+13x5=35+65=100

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