[(3x + 3) / A ^ 2] - 2 is greater than (1-2x) / A to solve inequality

[(3x + 3) / A ^ 2] - 2 is greater than (1-2x) / A to solve inequality

a≠0
So a ^ 2 > 0
Double a ^ 2
3x+3-2a^2>a-2ax
(2a+3)x>2a^2+a-3=(2a+3)(a-1)
therefore
a>-3/2,x>a-1
A = - 3 / 2, no solution
a

What is the solution of x ^ 3-3x ^ 2 + 2x = 0

It is proposed that x (x ^ 2-3x + 2) = 0
So, x = 0 or x ^ 2-3x + 2 = 0
Solve the quadratic equation x ^ 2-3x + 2 = 0 to get x = 1 or x = 2
To sum up, x = 0 or x = 1 or x = 2

875 × 2 / 9 △ 4 / 7 =?
Please, I'm in a hurry!

875 × 2 / 9 △ 4 / 7
=7 / 8 by 2 / 9 by 7 / 4
=49/144