Yes, please give me the answer It is known that in one square kilometer of land, the energy obtained by the sun in one year is equivalent to the energy generated by burning 1.3 × 10 5-th-power tons of coal. So, in China's territory of 9.6 × 10 6-th-power square kilometer, the energy obtained from the sun in one year is equivalent to the heat generated by burning about how many tons of coal?

Yes, please give me the answer It is known that in one square kilometer of land, the energy obtained by the sun in one year is equivalent to the energy generated by burning 1.3 × 10 5-th-power tons of coal. So, in China's territory of 9.6 × 10 6-th-power square kilometer, the energy obtained from the sun in one year is equivalent to the heat generated by burning about how many tons of coal?

It can be seen from the question that t = 9.6 × 10 to the 6th power × 1.3 × 10 to the 5th power = 1.248 × 10 to the 12th power

Yes, come on
1. A car starts from place a and travels at a speed of 55 kilometers per hour for 10 minutes to arrive at place B. how many kilometers is the distance between the two places?
2. The width of a rectangle is five seventh of a meter, and the length is twice of the width
3. For some apples, give 30% of them to Xiao Zhang, give the remaining 20% less than 2 to Xiao Wang, and then give the rest to Xiao Li. In this way, Xiao Li gets 28 more apples than Xiao Zhang. How many apples are there in all?
4. For a project, it takes 10 days for team a to complete it alone, and 15 days for team B to complete it alone. Now after two days of joint construction, there are still 40 meters left. How many meters is the total length of the project?

1.55 * 1 / 6 = 55 / 6 km, 2.5 / 7 * 2 = 10 / 7 m [length] 10 / 7 * 5 / 7 = 50 / 49 M2 3. Suppose there are x apples. (x * 30%) + 28 = x * (1-30%) - (x * (1-30%) * 20% - 2) (x * 0.3) + 28 = x * 0.7 - (x * 0.7 * 0.2-2) 0.3 * x + 28 = 0.7 * x - (0.14 * X-2) 0.3 * x + 28 = 0.7 * x-0.14 * x + 2 = 0.56 * x + 20

I'm waiting online for answers and ideas to 2 math problems
First, if the lengths of two sides of an isosceles triangle are the two roots of the equation x ^ 2-6x + 8 = 0, then the circumference of the triangle
The second. X ^ 4-x ^ 2-6 = 0 with substitution method solution. Mathematics is not very good, ask you to help

（1）x^2-6x+8=0
Factorization
(x-2)(x-4)=0
So these two sides are two and four
The third side is 4 (if it's 2, it's not a triangle)
The perimeter of the triangle is 2 + 4 + 4 = 10
(2) Let t = x ^ 2
Then T ^ 2-t-6 = 0
Factorization
(t+2)(t-3)=0
X ^ 2 = t = - 2 (rounding) or 3
x^2=3
X = ± root 3