A and B leave from AB and meet at the midpoint of 30 km. It is known that the speed of a is 1.5 times that of B, and ab is thousands of meters away

They meet at a distance of 30 km from the midpoint. When they meet, car a walks (30 × 2) km more than car B
The speed of car a is 1.5 times that of car B, and the distance of car a is 1.5 times that of car B when meeting
The distance between two places of AB is 30 × 2 ÷ (1.5-1) × (1 + 1.5) = 300 (km)

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