Let the sum of the first n terms of the sequence {an} be Sn, and (3-m) Sn + 2man = m + 3 (n ∈ n *). Where m is a constant, m ≠ - 3 and m ≠ 0, please solve one step (2) If the common ratio of sequence {an} satisfies q = f (m) and B1 = A1, BN = 32 F (bn-1) (n ∈ n *, n ≥ 2) bn }For the arithmetic sequence, and BN If B 1 = a 1 = 1, q = f (m) = 2m m + 3, n ∈ N and N ≥ 2, BN = 32 f (bn-1) = 32 & # 8226; 2bn-1 bn-1 + 3, can we explain it? (# 8658); we get bnbn-1 + 3bn = 3bn-1 & # 8658; 1bn-1 bn-1 = 13.; {1bn} is the first term of 1, and 13 is the arithmetic sequence of tolerance, so BN = 3N + 2 Proving {1 / BN} as arithmetic sequence And find BN

Let the sum of the first n terms of the sequence {an} be Sn, and (3-m) Sn + 2man = m + 3 (n ∈ n *). Where m is a constant, m ≠ - 3 and m ≠ 0, please solve one step (2) If the common ratio of sequence {an} satisfies q = f (m) and B1 = A1, BN = 32 F (bn-1) (n ∈ n *, n ≥ 2) bn }For the arithmetic sequence, and BN If B 1 = a 1 = 1, q = f (m) = 2m m + 3, n ∈ N and N ≥ 2, BN = 32 f (bn-1) = 32 & # 8226; 2bn-1 bn-1 + 3, can we explain it? (# 8658); we get bnbn-1 + 3bn = 3bn-1 & # 8658; 1bn-1 bn-1 = 13.; {1bn} is the first term of 1, and 13 is the arithmetic sequence of tolerance, so BN = 3N + 2 Proving {1 / BN} as arithmetic sequence And find BN

I'm sorry, you're really puzzling. Let's take a look at my problem-solving process. I'll do it again: 1. (3-m) s (n) + 2mA (n) = m + 3N = 1, (3-m) s (1) + 2mA (1) = m + 3A (1) = 1 (3-m) s (n-1) + 2mA (n-1) = m + 3 (3 + m) a (n) = 2mA (n-1) a (n) / a (n-1) = 2m / (3 + m) = QA (n) = a (1) Q ^ (n-1) = [2m / (M

The sum of the first n terms of the sequence {an} is Sn = npan (n belongs to N +), and A1 is not equal to A2 (1). Find the value of the constant P (2). Prove that the sequence {an} is an arithmetic sequence
An is not an arithmetic sequence. P has no specific value, but it is not equal to 1,

Choose B
This is a theorem. If the first n terms of a sequence and Sn = k * q ^ n, then the sequence is equal ratio sequence; if Sn = an ^ 2-B, then the sequence is equal difference sequence