If α belongs to (0,2 parts of π), β belongs to (2 parts of π, π), sin (α + β) = 65 parts of 33, cos β + negative 13 parts of 5, then what is sin α equal to

If α belongs to (0,2 parts of π), β belongs to (2 parts of π, π), sin (α + β) = 65 parts of 33, cos β + negative 13 parts of 5, then what is sin α equal to


α∈(0,π/2),β∈(π/2,π）
So, α + β ∈ (π / 2,3 π / 2)
sin(α+β)=33/65,cos(α+β)=-56/65
And β ∈ (π / 2, π)
cosβ=-5/13,sinβ=12/13,
So,
sinα=sin(α+β-β)=sin(α+β)cosβ-cos(α+β)sinβ=3/5



Sin (π / 4-A) = 3 / 5, sin (π / 4 + b) = 12 / 13, where 0


sin(π/4-a)=3/5
sin(a-π/4)=-3/5
0

Elden Ring Premiere

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