Given that the final edge of angle α passes through point P (x, - 2) (x ≠ 0), and cos α = (√ 3 / 6) x, find sin α + 1 / Tan α

Given that the final edge of angle α passes through point P (x, - 2) (x ≠ 0), and cos α = (√ 3 / 6) x, find sin α + 1 / Tan α

According to the meaning of the title
(cosα)^2=x^2/(2+x^2)=(（√3/6）x)^2
The simplification results in x = √ 10 or x = - √ 10
Calculated separately
Sin α = √ 6 / 6, cos α = √ 30 / 6 or cos α = - √ 30 / 6
Further calculation shows that
1 / Tan α = cos α / sin α = √ 5 or = - √ 5
So sin α + 1 / Tan α = √ 6 / 6 + √ 5 or = √ 6 / 6 - √ 5
tanα=

Given that the final edge of angle α passes through point P (x, - 2) (x ≠ 0) and cos α = (√ 3 / 6) x, find the values of sin α and Tan α

x=xy= - √2r=√(x^2+2)cosα=(√3/6)xcosα=x/√(x^2+2)(√3/6)x=x/√(x^2+2)√3/6=1/√(x^2+2)1/12=1/(x^2+2)x^2=10x=±√10r=2√3sinα=y/r= -√2/(2√3)= - √6/6cosα=±√30/6tanα=±√5/5

Given that the coordinates of a point P on the final edge of the angle α are (x, - 2) (x ≠ 0) and cos α = x / 3, the values of sin α and Tan α are obtained

The coordinates of P are (x, - 2)
Then Tan α = - 2 / X
cosα=x/3
sinα/cosα=tanα
So sin α = cos α Tan α = x / 3 * (- 2 / x) = - 2 / 3

Given a point P (x, - 2) of the final edge of the angle θ, x < 0 and cos θ = x / 3, find sin θ and Tan θ

Angle θ the third quadrant angle, sin θ < 0, Tan θ > 0
Sin 2 θ + cos 2 θ = 1, sin θ = - radical [(9-x 2) / 9]
Tan θ = sin θ / cos θ = radical [(9-x 2) / x 2]

(sin60 °) squared + (cos60 °) squared - tan45 ° =?

(sin 60 °) square + (COS 60 °) square - Tan 45 ° = 1-1 = 0

The value of Tan 30 ° and COS 60 ° can be obtained by using △ ABC, which is an equilateral triangle

Let AB = AC = BC = 2 be ad vertical BC because it is equilateral △ so BD = CD = 1
The tangent angle bad = angle CAD = 30 ° using Pythagorean theorem, we can get ad = root 3, Tan 30 ° = BD / ad = 3 / 3 root sign 3
cos60°=BD/AB=1/2

What is the trigonometric function formula sin30 ° equal to

1/2
Sin45 ° = radical 2 / 2
Sin60 ° = radical 3 / 2
It's regular

Sin30,60,90 is equal to the root number, the first mock exam tomorrow!

sin30=1/2.sin60=√3/2,sin90=1

What is 2cos 60 degrees plus sin 30 degrees plus root 3 cot 60 degrees

2cos60°＋sin30°＋√3cot60
2×1/2+1/2+√3×√3/3
=1+1/2+1
=2.5

1、 sin30°=?

1 / 2 is 0.5