It is known that a, B and C are the three side lengths of △ ABC respectively, and a 2 + 2 B 2 - 2 ab-2 BC + C 2 = 0, judge the shape of △ ABC, and find out the detailed process! 1. It is known that a, B, C are the three sides of △ ABC respectively, and a 2 + 2B 2 - 2ab-2bc + C 2 = 0 is used to judge the shape of △ ABC

It is known that a, B and C are the three side lengths of △ ABC respectively, and a 2 + 2 B 2 - 2 ab-2 BC + C 2 = 0, judge the shape of △ ABC, and find out the detailed process! 1. It is known that a, B, C are the three sides of △ ABC respectively, and a 2 + 2B 2 - 2ab-2bc + C 2 = 0 is used to judge the shape of △ ABC

This is an equilateral triangle (M + 6) ^ 2 = 9 × 4 × (m-2) m ^ 2 + 12m + 36 = 36m-72m ^ 2-24m + 108 = 0 (M-18) (M-6) = 0m1 = 1

If a, B and C are the lengths of the three sides of △ ABC and satisfy A2 + 2B2 + c2-2b (a + C) = 0, then the shape of the triangle is______ .

From the known condition A2 + 2B2 + c2-2b (a + C) = 0, it is obtained that,
（a-b）2+（b-c）2=0
∴a-b=0，b-c=0
That is, a = B, B = C
∴a=b=c
So the answer is an equilateral triangle

0

C△abc=12cm
A + B + C = 12cm
That is 3B = 12 (a + C = 2b)
B=4
Equations
a+c=2b=8
c-a=2
Add up
2c=10
C=5
A=3
So a = 3 B = 4 C = 5

It is known that a, B, C are the three sides of a right triangle ABC, and the hypotenuse C is obtained by (a 2 + B 2) 2 (a 2 + B 2) - 15 = 0

（a²+b²)²－2(a²+b²)－15＝0
（a²+b²-5)(a²+b²+3)=0
A? + B? = 5 or a? + B? = - 3 (omitted)
c²=5
c=√5

It is known that a, B, C are the three sides of the triangle ABC. (1) when the square of B + 2Ab = the square of C + 2Ab, try to judge the shape of triangle ABC; (2) Try to judge the relation between the square of polynomial a - the square of B + the square of C - 2Ac and explain the reason

b^2+2ab=c^2+ab
Then B ^ 2 = C ^ 2
∵a、b＞0
∴a=b
ν Δ is an isosceles triangle
（2）a^2-b^2+c^2-2ac
=a²-2ac+c²-b²
=(a-c)²-b²
=(a-c+b)(a-c-b)
The sum of the two sides of a triangle is greater than the third
(a-c+b)>0 (a-c-b)

It is known that ABC is the length of the three sides of a triangle. (1) when B2 + 2Ab = C2 + 2Ac, try to determine which kind of triangle △ ABC belongs to It is known that ABC is the length of the three sides of a triangle. (2) the sign of judging the value of a2-b2-2bc-c2, and giving reasons

Are you still online? Grab the fastest

(1 / 2) if the side length of ABC is a, B, C (1) when the square of B + 2Ab = the square of C + 2Ac, try to judge the shape of ＋ ABC. (2) judge the plane of algebraic formula a (1 / 2) if the side length of ＋ ABC is a, B, C (1) when the square of B + 2Ab = the square of C + 2Ac, try to judge the shape of ＋ ABC. (2) judge the square of algebraic formula a - the square of B+

b²+2ab+a²=c²+2ac+a²
(a+b)²=(a+c)²
a+b=a+c
B=c
The ABC is an isosceles triangle
See your second question for the answer to the second question

It is known that a, B, C are the three sides of △ ABC and satisfy the relationship a ^ 2 + C ^ 2 = 2Ab + 2ac-2b ^ 2. Try to judge the shape of △ ABC

0

It is known that a, B, C are the three sides of △ ABC and satisfy the relationship a ^ 2 + C ^ 2 = 2Ab + 2ac-2 (b ^ 2), so as to judge the shape of △ ABC

For example, when a = 9, B = 8, C = 5, the relation a ^ 2 + C ^ 2 = 2Ab + 2ac-2 (b ^ 2) is also satisfied
If the relation is changed to a ^ 2 + C ^ 2 = 2Ab + 2bc-2 (b ^ 2), it will be simple,
A ^ 2-2ab + B ^ 2 + B ^ 2-2bc + C ^ 2 = 0, i.e. (a-b) ^ 2 + (B-C) ^ 2 = 0, so a = B and B = C,
So △ ABC is an equilateral triangle

It is known that a, B and C are the lengths of the three sides of △ ABC. 1. When the second power of B + 2Ab = the second power of C + 2Ac, we can judge the shape of △ ABC; 1、 ABC, C is the length of three sides 1. Judge the shape of △ ABC when the power of B + 2Ab = the power of C + 2Ac; 2. Verification: the 2nd power of a - the 2nd power of B + the 2nd power of C - 2Ac

In this paper, the results show that B 2 + 2 ab = C 2 + 2 AC, B 2 + 2 ab + a 2 = C 2 + 2 AC + a 2, then (B + a) 2 = (c + a) 2. Therefore, B = C. Therefore, the triangle is an isosceles triangle