The distance from each point on the circle to the center of the circle is equal to______ The points whose distance from the center of the circle is equal to the radius are all in the______ .

The distance from each point on the circle to the center of the circle is equal to______ The points whose distance from the center of the circle is equal to the radius are all in the______ .

The distance from each point on the circle to its center is equal to the radius of the circle
So the answer is the radius of the circle, on the circle

A line whose distance from the center of the circle is not equal to the radius is not the tangent of the circle I worked out three inverse propositions, First, if the tangent of a circle is not a radius, the radius of your distance from the center of the circle is not a straight line 2： If the straight line of the circle is not a radius, the radius of your distance to the center of the circle is not tangent 3： If the line is not tangent to the circle, your distance from the center of the circle is not equal to the radius If I'm all wrong, So it's changed into that correction. lower

The distance from the straight line to the center of the circle is not equal to the radius -- > the line is not the tangent of the circle
So the inverse proposition is the opposite
If a line is not tangent to a circle, then its distance from the center of the circle is not equal to the radius

If the distance from the center of a circle to a straight line is not equal to the radius of a line, it is not a tangent of a circle

The original proposition should be "a straight line whose distance to the center of a circle is not equal to the radius is not the tangent line of the circle."
No proposition: the line whose distance from the center of the circle is equal to the radius is the tangent line of the circle
Inverse no proposition: the distance between the tangent line and the center of a circle is equal to the radius

The true proposition in the following propositions is: the tangent of a circle is a straight line whose distance from the center of a circle to it is equal to the length of the radius of the circle The true proposition in the following propositions is () A. The tangent of a circle is a straight line whose distance from the center of the circle is equal to the radius of the circle B. Point a is on the straight line L, and the radius of circle O is R. if OA = R, then l is the tangent of circle o C. If the diameter of the circle O is a, then the distance of the straight line L at the point O is d. if d = a, then l is the tangent of the circle o The false proposition is () A. A circle whose radius is a right angle must be tangent to the other right angle B. The circle with the vertex of the isosceles triangle as the center and the height on the bottom as the radius is tangent to the base C. The center point of the hypotenuse of an isosceles right triangle is taken as the center of the circle, and half of the right angle side is a circle with radius, which is tangent to the two right angles

1 A is a true proposition, (B is wrong, when a straight line intersects a circle and the intersection point is a)
2 A is a false proposition

What is the inverse proposition of tangent of a line whose distance to the center of a circle is not equal to its radius

The inverse proposition of the tangent of a line whose distance to the center of a circle is not equal to its radius is not a circle
The distance from the tangent line of a circle to the center of the circle is not equal to the radius

Why is the distance from the center to the tangent equal to the radius of the circle

This problem can be interpreted as "prove that the line between tangent line and center of circle is perpendicular to tangent line."
With the method of proof to the contrary: suppose that the line between the tangent point of the tangent line and the center of the circle is not perpendicular to the tangent line
Make the vertical line op of tangent line through the center of circle O, the vertical point is p; the tangent point of tangent and circle is p '; the tangent line is set as ab
We can take another point P '' on AB so that p '' p = PP '
Because OP is perpendicular to AB, we can get OP '= OP' '
So p '' is on a circle, which is in contradiction with ab being tangent to the circle
Therefore, the line between tangent point and center of circle is perpendicular to tangent line

What is the solution of the equation 2x squared plus 5x minus 3 equal to 0

What is the solution of the equation 2x squared plus 5x minus 3 equal to 0
2x^2+5x-3=0
This problem can be solved by factorization
It can be decomposed into (2x-1) (x + 3) = 0
Then 2x-1 = 0 or x + 3 = 0
So:
x1=1/2
x2=-3

Given that the distance between the centers of two circles is 5 and the radius of two circles is the two roots of the equation x ^ 2-4x + 1 = 0, then the position relationship between the two circles is obtained A contains B intersection C exfoliation D-inscribed

x1+x2=4

It is known that the distance between the centers of two circles is equal to 5, and the diameter of the two circles is the two roots of the equation x square-10x + 3 = 0. Try to judge the position relationship between the two circles

The diameters of the two circles are the two roots of the equation x ^ 2-10x + 3 = 0
From the Veda theorem, we get
The sum of the two diameters is 10
The center distance between the two circles is 5
The position relationship between the two circles may be circumscribed

Given that the center distance of two circles is 5, and the diameter of two circles is the two roots of the equation x square - 10x + 3 = 0, try to judge the position relationship between the two circles?

Let the radius of two circles be R1, R2
From the meaning of the title: 2r1 + 2r2 = 10
That is, R1 + R2 = 5
So the distance between the centers of the circle is equal to the sum of the radii
Happy New Year!