As shown in the figure, the image with the known first order function y = - 4 / 3x + 8 intersects with X axis and Y axis at points a and B respectively, AE bisects angle Bao and intersects Y axis at point E 1. Find point a coordinate 2. Find the analytic formula of straight line AE 3. BF at point B, perpendicular to AE, perpendicular to F, connected with of (1) . prove that of = BF (2) . find the area of the triangle OFB

As shown in the figure, the image with the known first order function y = - 4 / 3x + 8 intersects with X axis and Y axis at points a and B respectively, AE bisects angle Bao and intersects Y axis at point E 1. Find point a coordinate 2. Find the analytic formula of straight line AE 3. BF at point B, perpendicular to AE, perpendicular to F, connected with of (1) . prove that of = BF (2) . find the area of the triangle OFB

Let y = 0, - 4 / 3x + 8 = 0 to get: x = 6,  a (6,0), 2 (OB = 8, OA = 6,  AB = 10,  AB = 10, ? AE bisection  Bao,  OE / be = OA / AB = 6 / 10 = 3 / 5, oe = 3, e (0,3),  straight-line AE analytic formula: y = 1 / 2x + 3, 3 ? BFA = ? BFA = 90, ᙽ a, a, B, F, o four points are circular, F, ∠ BAF = ∠ BOF, ∵

In the plane rectangular coordinate system, the line L1: y = - 4 / 3x + 8 intersects the coordinate axis at two points AB, the bisector of angle Bao intersects the Y axis at point D, and the straight line passing through point D is L2 = KX + In the plane rectangular coordinate system, the line L1: y = - 4 / 3x + 8 intersects the coordinate axis at two points AB, the bisector of angle Bao intersects the Y axis at point D, and the straight line L2 = KX + B (k is not equal to 0) crosses X axis at point C (- 4,0) (1) : find the length of ab (2) CDO: proof of total triangle (3) : find the coordinates of point D and the analytic formula of line L2 (4) : find the point P on the X axis so that the area of triangle PbO is half of the area of triangle ace

① If a (6,0) and B (0,8) are known according to L1 equation, then AB length is 10
② The results show that △ ade ≌ △ ADO, that is, de = do
We also know △ BDE ≌ △ CDO by ∠ bed = ∠ cod, ≌△ CDO
③ From the formula of half angle, the tangent of ∠ Dao is 1 / 2
The answer you gave is not limited in length

It is known that the image of the function y = - 3 / 4x + 6 intersects with point a and B, AE bisects ∠ Bao, and intersects X axis at point E 1. Find point B coordinate 2. Find the expression of straight line AE 3. Make BF ⊥ AE through point B, connect with of, try to judge the shape of ⊥ ob, and calculate the area of ⊥ OFB 4. If the known condition "AE bisects ∠ Bao, intersecting X axis at point e" is changed to "point E is a moving point on line ob (point E does not coincide with point O, b)", pass through point B as BF ⊥ AE, set foot as F, let OE = x, BF = y, try to find the functional relationship between Y and X, and write out the function definition domain

1) Let y = 0, then 0 = (- 3 / 4) x + 6, x = 8, so point B is (8,0); 2). AB = √ (OA + OB) = 10. Make em vertical AB perpendicular to M. ∵ AE bisdivide

In the plane rectangular coordinate system, the straight line y = KX + B (k is a constant and K ≠ 0) intersects X and y at two points a and B, and the radius of O is 5 units of the root sign Q: let k = - 1 / 2, the straight line y = KX + B, divide the circle into two sections, and the ratio of arc length is 1:2, and find the value of B

If so, the solution is as follows: circle equation: x ^ 2 + y ^ 2 = 5, straight line equation is: y = - X / 2 + B, intersect with X axis and Y axis at a and B respectively, let intersect with circle at two points c and D, according to known conditions, CD inferior arc / CD superior arc = 1 / 2, then CD inferior arc to circle center angle is 120 degrees, make om ⊥ CD, then M is CD midpoint

In the plane rectangular coordinate system xoy, it is known that circle 0: x2 + y2 = 16, points P (1,2), m, n are two different on circle o

Is this the title
In the plane rectangular coordinate system xoy, it is known that the circle O: x2 + y2 = 16, points P (1,2), m, n are different two points on circle o
If vector PQ = vector PM + vector PN, then the minimum value of | PQ | is?

As shown in the figure, in the plane rectangular coordinate system xoy, it is known that the circle B: (x-1) ^ 2 + y ^ 2 = 16 and point a (- 1,0), P is the moving point on circle B, and the vertical bisector of line PA is straight Line Pb is at point R, the locus of point R is marked as curve C, and the intersection point of curve C and positive half axis of X axis is marked as Q. the intersection point of straight line passing through the origin and not coincident with X axis and curve C is marked as m, N, connecting QM and QN, respectively crossing straight lines X = t (t is a constant, and t ≠ 2) at points E and F, let the ordinates of EF be Y1 and Y2, and calculate the value of Y1 * Y2 (expressed by T)

A good friend has been asking me in hi for a long time, which is delayed ∵ the vertical bisectionline of line PA intersectthe straight line Pb at point R 124\124\124\\124\124\\\124124124124124124; | | | | | | | | | | | | | | | 124; | 124; | | 124; thenq (2,0) let m

In the plane rectangular coordinate system xoy, the equation of the line L is 3x + 4y-6 = 0. Analogy with this proposition, we can get that: in the space rectangular coordinate system o-xyz, plane a passes through the point (2,2,0) and is perpendicular to the vector u = (3,4,5). If any point P (x, y, z) on the plane a, the equation of plane a is________________ .

You can draw a picture first
Let m (x, 3x / 4-3)
Om = in fact, it is to calculate the distance from the right angle point to the right angle side with the side length of 3, 4, 5
Let om = t root number (9-t ^ 2) + root number (16-t ^ 2) = 5, then t = 12 / 5
So x ^ 2 + (3x / 4-3) ^ 2 = 144 / 25
X = 6 / 5
So m (6 / 5, - 21 / 10)

In the plane rectangular coordinate system xoy, a (- 1,0) B (0,2) C (2,0) (1) solve the equation of the straight line L which passes through the point C and is perpendicular to ab Mathematical problems in the plane rectangular coordinate system xoy. A (- 1,0) B (0,2) C (2,0) (1) find the equation of the straight line L passing through point C and perpendicular to ab (2) find the equation of the circle with point C as the center and tangent to ab

（1）AB:y=2x+2,
If the perpendicular foot is D, let CD: y = - 1 / 2x + B
By substituting x = 2, y = 0, we get:
0=-1/2×2+b
B=1
That is CD: y = - 1 / 2x + 1
(2) Simultaneous y = 2x + 2, y = - 1 / 2x + 1
The coordinates of point D are (- 2 / 5,6 / 5). It can be seen from the question that point D is the intersection point of circle and ab
(X-2) square + y square = 36 / 5

It is known that circle C passes through two points a (3,2) and B (1,6), and its center is on the straight line y = 2x It is known that circle C passes through two points a (3,2) and B (1,6), and its center is on the straight line y = 2x. (1) find the equation of circle C; (2) if the straight line L passes through point P (- 1,3) and is tangent to circle C, find the equation of straight line L,

The center of the circle is on the vertical line of ab
AB slope -2, midpoint (2,4)
The slope of vertical line is 1 / 2, x-2y + 6 = 0
y=2x
Center C (2,4)
r=AC=√5
(x-2)²+(y-4)²=5
The distance from the center to the tangent is equal to the radius
y-3=k(x+1)
|2k-4+3+k|/√(k²+1)=√5
figure out
2x-y+5=0,x+2y-5=0

It is known that circle C passes through two points a (3,2) and B (1,2), and its center is on the straight line y = 2x, (1) find the equation of circle C (2) If the line L passes through point B (1,2) and is tangent to circle C, find the equation of line L

There is a second question. Yes, plus - O - thank you