FeS dissolved in dilute nitric acid Dissolution of ferrous sulfide in dilute nitric acid
Reaction formula of ferrous sulfide and excessive nitric acid:
FeS+6HNO3=Fe (NO3)3+H2SO4+2H2O+3NO↑
2 Valence ferrous iron lost one electron and increased 1 valence to 3 valence iron and negative 2 valence sulfur lost 8 electrons and increased 8 valence to 6 valence sulfur.
The electron gain and loss in redox reaction are conserved.
FeFeO and dilute nitric acid reflect the formation of NOd equation?
Fe sufficient
3Fe+8HNO3==3Fe (NO3)2+2NO 4H2O
Dilute nitric acid sufficient
Fe+4HNO3==Fe (NO3)3+NO↑+2H2O
FeO+4HNO3=Fe (NO3)3+NO2+2H2O
3FeO+10HNO3(dilute)=3Fe (NO3)3+5H2O+NO↑
Fe sufficient
3Fe+8HNO3==3Fe (NO3)2+2NO 4H2O
Dilute nitric acid content
Fe+4HNO3==Fe (NO3)3+NO↑+2H2O
FeO+4HNO3=Fe (NO3)3+NO2+2H2O
3FeO+10HNO3(dilute)=3Fe (NO3)3+5H2O+NO↑
Fe sufficient
3Fe+8HNO3==3Fe (NO3)2+2NO 4H2O
Dilute nitric acid sufficient
Fe+4HNO3==Fe (NO3)3+NO 2H2O
FeO+4HNO3=Fe (NO3)3+NO2+2H2O
3FeO+10HNO3(dilute)=3Fe (NO3)3+5H2O+NO↑