FeS dissolved in dilute nitric acid Dissolution of ferrous sulfide in dilute nitric acid

FeS dissolved in dilute nitric acid Dissolution of ferrous sulfide in dilute nitric acid

Reaction formula of ferrous sulfide and excessive nitric acid:
FeS+6HNO3=Fe (NO3)3+H2SO4+2H2O+3NO↑
2 Valence ferrous iron lost one electron and increased 1 valence to 3 valence iron and negative 2 valence sulfur lost 8 electrons and increased 8 valence to 6 valence sulfur.
The electron gain and loss in redox reaction are conserved.

FeFeO and dilute nitric acid reflect the formation of NOd equation?

Fe sufficient
3Fe+8HNO3==3Fe (NO3)2+2NO 4H2O
Dilute nitric acid sufficient
Fe+4HNO3==Fe (NO3)3+NO↑+2H2O
FeO+4HNO3=Fe (NO3)3+NO2+2H2O
3FeO+10HNO3(dilute)=3Fe (NO3)3+5H2O+NO↑

Fe sufficient
3Fe+8HNO3==3Fe (NO3)2+2NO 4H2O
Dilute nitric acid content
Fe+4HNO3==Fe (NO3)3+NO↑+2H2O
FeO+4HNO3=Fe (NO3)3+NO2+2H2O
3FeO+10HNO3(dilute)=3Fe (NO3)3+5H2O+NO↑

Fe sufficient
3Fe+8HNO3==3Fe (NO3)2+2NO 4H2O
Dilute nitric acid sufficient
Fe+4HNO3==Fe (NO3)3+NO 2H2O
FeO+4HNO3=Fe (NO3)3+NO2+2H2O
3FeO+10HNO3(dilute)=3Fe (NO3)3+5H2O+NO↑