A cuboid wood (as shown in the figure), after cutting a cuboid with a volume of 72 decimeters, the remaining part is exactly a cuboid with a prism length of 3 decimeters. Find the surface area of the original cuboid.

A cuboid wood (as shown in the figure), after cutting a cuboid with a volume of 72 decimeters, the remaining part is exactly a cuboid with a prism length of 3 decimeters. Find the surface area of the original cuboid.

Original length:72÷(3×3)+3
=8+3
=11(Decimeters),
Surface area:11×3×4+3×3×2
=132+18
=150(Square decimeters);
Answer: The surface area of the original cuboid is 150 square centimeters.

When the height of a cuboid is increased by 3 dm, the surface area of the cuboid is 48 dm higher than that of the cuboid. Formulas! That's what the paper says! When the height of a cuboid is increased by 3 dm, the surface area of the cuboid is 48 dm higher than that of the cuboid. Column formula! That's what the paper says!

48/4/3=4, The side length of the bottom of the box is obtained, the bottom is square, and the increased surface area is four side areas
So 48/4
4-3=1, Get cuboid height
4*4*1=16 To obtain cuboid volume

48/4/3=4, The side length of the bottom of the box is obtained, the bottom is square, and the increased surface area is four side areas.
So 48/4
4-3=1, Get cuboid height
4*4*1=16 To obtain cuboid volume