In the right triangle ABC, if the length of the hypotenuse BC is 24, find the trajectory equation of the right vertex a

In the right triangle ABC, if the length of the hypotenuse BC is 24, find the trajectory equation of the right vertex a

Make a circle with BC as its diameter, r = 12, and set the midpoint of BC as point O, and make it a rectangular coordinate system
Because of the right triangle ABC, the vertex A is on the circle and does not coincide with B and C
So the trajectory equation is x? 2 + y? 2 = 144 (x ≠ ± 12)

The hypotenuse of a right triangle is 20cm, and the length ratio of two right angles is 3:4 More details!

Let the two right angles be 3x cm and 4x cm respectively
Then 9x? + 16x? = 20? = 400
x²=400/25
X=4
So the length of the two right angles is 12 cm and 16 cm respectively

The hypotenuse of a right triangle is 20cm, and the length ratio of two right angles is 3:4? Be quick!

Let one of the two right angles be 3x, then the other is 4x
Thus (3x) ^ 2 + (4x) ^ 2 = 20 ^ 2 (Byrd's theorem)
9X^2+16X^2=400
25X^2=400
X^2=16
X=4
The lengths on both sides of the right angle are 12 and 16, respectively

The hypotenuse of a right triangle is 20cm, and the length ratio of the two right sides is 3:4

Let two right angles be 3x and 4x respectively
Then (3x) 2 + (4x) 2 = 20
9x²+16x²=400
25x²=400
x²=16
∵ x is a positive number
∴x=4
∴3x=12,4x=16
The area of the right triangle is 12 × 16 △ 2 = 96

The hypotenuse of a right triangle is 20 cm, and the ratio of the length of the two right sides is 3:4

Let two right angles be 3xcm and 4xcm,
Then (3x) 2 + (4x) 2 = 202,
The solution is: x = 4 or x = - 4 (omitted),
Then 3x = 3 × 4 = 12 (CM), 4x = 4 × 4 = 16 (CM),
That is, the two right angles are 12cm and 16cm

The hypotenuse of a right triangle is 20cm, and the length ratio of right angle side is 3:4. Find the length of two right angle sides

Let the right angle sides be 3x and 4x
According to the Pythagorean theorem a 2 + B 2 = C
(3x)²+(4x)²=20²
X=4
The right angle sides are 12cm and 16cm respectively

The hypotenuse of a right triangle is 10 cm, and the length ratio of the two right angles is 3:4 Find the length of two right angle sides and the height of oblique side

The length ratio of the two right angle sides is 3:4 = > from the Pythagorean bevel 5 = > 3:4:5 = (6): (8): 10
Two right angles 6 or 8; height on hypotenuse = multiplication of two right angles △ hypotenuse = 6 * 8 / 10 = 4.8

It is known that the length of the two right sides of a right triangle is 4cm, and the ratio of the length of the hypotenuse to the other right angle side is 5:3. If the length of the hypotenuse of the right triangle is 5x cm, then the equation is

(5x)²=4²+(3x)²
The solution x = 1 (omit - 1)
So the two right sides are 3cm 4cm long and 5cm long
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If one angle of a right triangle is 45 ° and the hypotenuse is 1, then the length of the other two sides is? What about the hypotenuse of 2 and 3?

One half change two two two three times sign two

Given the length of the right side of a right triangle, how to find the length of the hypotenuse? I haven't learned these things in my second year of junior high school,

Using the Pythagorean theorem: the square of the length of the hypotenuse equals the sum of the squares of the lengths of the right angles