A train moves in a straight line at an initial speed of two meters per second and an acceleration of 0.5 meters per second. Find (1) what is the speed of the train at the end of three seconds? (2)... A train moves in a straight line at an initial speed of two meters per second and an acceleration of 0.5 meters per second. Find (1) what is the speed of the train at the end of three seconds? (2) What is the average speed in the first four seconds?

A train moves in a straight line at an initial speed of two meters per second and an acceleration of 0.5 meters per second. Find (1) what is the speed of the train at the end of three seconds? (2)... A train moves in a straight line at an initial speed of two meters per second and an acceleration of 0.5 meters per second. Find (1) what is the speed of the train at the end of three seconds? (2) What is the average speed in the first four seconds?

v0=2m/s
a=0.5m/s^2
Train speed at the end of three seconds V3 = V0 + at = 2 + 0.5 * 3 = 3.5m/s
Train speed at the end of four seconds V4 = V0 + at = 2 + 0.5 * 4 = 4m / S
Average speed in the first four seconds = (V0 + V4) / 2 = (2 + 4) / 2 = 3m / S

A train finished crossing two iron bridges at a speed of 600 meters per minute. Crossing the second iron bridge is 5 seconds longer than the one. It is also known that the length of the two iron bridges is 50 meters shorter than twice the length of the first iron bridge. Try to find the length of each iron bridge?

Train speed = 600 m / min = 10 m / S
Bridge 2 - bridge 1 = 5 * 10 = 50m
Bridge 1 = bridge 2-50
Bridge 2 + 50 = 2 bridge 1 = 2 (bridge 2-50)
Bridge 2 = 150
Bridge 1 = 100

A train had to cross the first and second iron bridges at a speed of 600 meters per minute. It took 5 seconds more to cross the second iron bridge than the first iron bridge. It is also known that the length of the second iron bridge is 50 meters shorter than twice the length of the first iron bridge. Try to find the length of each iron bridge

If the length of the first railway bridge is x meters, then the length of the second railway bridge is (2x-50) meters, and the time required to cross the first railway bridge is x600 minutes. The time required to cross the second railway bridge is 2x − 50600 minutes. According to the meaning of the question, the equation x600 + 560 = 2x − 50600 can be listed, and the equation x + 50 = 2x-50 can be solved to obtain x = 100, ‡ 2x-50 = 2 × 100...

A train had to cross the first and second iron bridges at a speed of 600 meters per minute. It took 5 seconds more to cross the second iron bridge than the first iron bridge. It is also known that the length of the second iron bridge is 50 meters shorter than twice the length of the first iron bridge. Try to find the length of each iron bridge

If the length of the first railway bridge is x meters, then the length of the second railway bridge is (2x-50) meters, and the time required to cross the first railway bridge is x600 minutes. The time required to cross the second railway bridge is 2x − 50600 minutes. According to the meaning of the question, the equation x600 + 560 = 2x − 50600 can be listed, and the equation x + 50 = 2x-50 can be solved to obtain x = 100, ‡ 2x-50 = 2 × 100...

For a vehicle traveling along a flat and straight road, the speed is 36km / h, and the acceleration obtained after braking is 4m / S ^ 2. Calculate the displacement of the vehicle in the last 2 seconds Please solve it as soon as possible What the hell is it, huh

S = 1 / 2att = 1 / 2 * 4 * 2 * 2 = 8M

The speed of a car traveling along a flat and straight road is 36km / h, and the acceleration obtained after braking is 4m / S2 Find ① the distance from the start of braking to the stop of the car ② The speed at which the vehicle coasts half the distance from the start of braking to the stop ③ The distance from the start of braking to the stop when the sliding speed is half of the initial speed

(1) 2 * (- 4) * s = - 10 ^ 2 from 2As = 0-v0 ^ 2, s = 12.5m (2) 2 * (- 4) * 6.25 = VT ^ 2-10 ^ 2, VT = 5 times the root sign 2 (3) 2As = VT ^ 2-v0 ^ 2, 2 * (- 4) * s = (10 / 2) ^ 2-10 ^ 2, s = 9.375m pay attention to the conversion of units