Given the square Wx + a (W > 0) of the function f (x) = sin (2wx-6 π) - 4sin, the distance between the two highest points of the image is π (1) Let π (2) be the smallest increasing value of π (2) on the interval

Given the square Wx + a (W > 0) of the function f (x) = sin (2wx-6 π) - 4sin, the distance between the two highest points of the image is π (1) Let π (2) be the smallest increasing value of π (2) on the interval

(1) [2K π - 5 π / 12,2k π + π / 12] K is an integer sin (2wx - π / 6) = sin2wx * cos π / 6 - cos2wx * sin π / 6 = √ 3 / 2 * sin2wx - 1 / 2 * cos2wx. Because cos2wx = the square Wx of 1-2sin, the square Wx of 4sin = 2 - 2cos2wx f (x) = √ 3 / 2 * sin2wx - 1 / 2 * cos2wx -
Four
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The distance between the nearest two points in the intersection of the image of the function y = sin (ω X - π / 3) and the straight line y = 1 / 2 is π / 3, and the solution of the function is given
The distance between the nearest two points in the intersection of the image of the function y = sin (ω X - π / 3) and the line y = 1 / 2 is π / 3, and W is obtained
The first intersection point of this function and y = 1 / 2 is π / 6 = ω X - π / 3, and x = π / (2 ω)
The second intersection is 5 π / 6 = ω X - π / 3, and x = 7 π / (6 ω)
The distance between the two points is "the distance between the nearest two points in the intersection of the image of the function y = sin (ω X - π / 3) and the line y = 1 / 2", so 7 π / (6 ω) - π / (2 ω) = 2 π / (3 ω) = π / 3
So ω = 2
It takes 24 seconds for a train to pass through the first tunnel with a length of 360 meters, and 16 seconds for it to pass through the second tunnel with a length of 224 meters
Train speed: (360-224) △ 24-16, = 136 △ 8, = 17 (M / s), body length: 24 × 17-360, = 408-360, = 48 (m); answer: the body length of this train is 48 meters, and the speed is 17 meters per second
Fourth grade of primary school Volume II mixed operation problem, integer, not decimal
125－25×6 （135＋75）÷（14×5） 120－60÷5×5
1024÷16×3 （135＋415）÷5+16 1200－20×18
720-720÷15 (360-144)÷24×3 240+480÷30×2
225-10×（6+13） （120×2+120）÷9 164-13×5+85
330÷(65－50) 128－6×8÷16 64×(12＋65÷13)
19×96－962÷74 10000－(59＋66)×64 5940÷45×(798－616)
(315×40－364)÷7 12520÷8×(121÷11) (2010－906)×(65+15)
（20＋120÷24）×8 106×9－76×9 117÷13＋36×15
3774÷37×（65+35） 540－（148+47）÷13 （308—308÷28）×11
I've been playing for a long time. Can I help you? Please choose me. Please give me extra points
（10＋120÷24）×5 （238+7560÷90）÷14 21×（230－192÷4）
19×96－962÷74 10000－(59＋66)×64 5940÷45×(798－616)
(315×40－364)÷7 735×（700－400÷25） 1520－（1070＋28×2）
9405-2940÷28×21 920-1680÷40÷7 690+47×52-398
148+3328÷64-75 360×24÷32+730 2100-94+48×54
51+（2304-2042）×23 4215+（4361-716）÷81 （247+18）×27÷25
36-720÷（360÷18） 1080÷（63-54）×80 （528+912）×5-6178
1.350-21x5 2.100 divided by 25 + 10
15*45/3=225
24+30/6=29
66-20*3=6
14*3+38=80
256/16-12=4
17*3+151=202
32*8+43=299
89+78-56=111
60*9-38=502
77+24/8=80
Guangfa Huafu
How to calculate the addition and subtraction of different denominator fractions
Find the least common multiple of the denominator! Then see how many times the least common multiple is the denominator; multiply the multiple with the numerator. Then the denominator remains unchanged. Add and subtract the numerator
Sum (A-1) + (a ^ 2-2) + +(a ^ N-N)
I have no idea at all
Remove the brackets. The first term in each bracket forms an equal ratio sequence, and the second term forms an equal difference sequence. Then there is a set of formulas
The distance between a and B is 420 km. The car is planned to travel 7 hours from a to B. the actual distance is 10 km more than the planned distance. How many hours does it actually arrive?
How much is the income of two large and small buses between city a and city B? (one way ticket 26 yuan)
Cart: 46 people from a to B, 44 people from B to a. Car: A-B 32, B-A 28.
Planned speed: 420 △ 7 = 60 (km / h)
Actual speed: 60 + 10 = 70 (km / h)
Actual time: 420 △ 70 = 6 (hours)
The plan is 420 / 7 per hour = 60 km
Actual 60 + 10 = 70 km / h
So it's actually 420 / 70 = 6 hours
Stroke speed: 420 / 7 = 60km / h;
Actual speed: 60 + 10 = 70km / h;
Actual time: 420 / 70 = 6 hours.
T = 420 △ 7 + 10 = 6 (hours)
The actual arrival time is 6 hours
The income of carts is: (46 + 44) × 26 = 2340 (yuan)
The income of the car is: (32 + 28) × 26 = 1560 (yuan)
420÷（420÷7+10）
＝420÷（60+10）
＝420÷70
= 6 (hours)
A: the actual arrival time is 6 hours.
For a decimal, if the decimal part is increased by 2 times, the number will be 3.8. If the decimal part is increased by 5 times, the number will be 5.6. What is the original number?
5.6-3.8 = 1.8 is three times the decimal part
So the fractional part is 0.6
So the original number is 3.8-2 * 0.6 = 2.6
How to add and subtract fractions with different denominators? For example, 1 / 2 + 1 / 4, why = 2 / 4 + 1 / 4? How do 2 and 1 come out?
The addition and subtraction of fractions with different denominators is the same as the addition and subtraction of integers. The so-called digit alignment means that the counting units are the same, while the fractional units of 1 / 2 + 1 / 4 are different. You can't add and subtract directly. For example, if you divide a cake into two equal portions and eat one equal portion, you can eat two equal portions with four equal portions, The other of these four parts together is the sum of 2 and 1, that is, 1 / 2 + 1 / 4 = 2 / 4 + 1 / 4 = (1 + 2) / 4 = 3 / 4
1×1 2×2 3×3 … How to sum n × n
1²+2²+3²+.+n²=n(n+1)(2n+1)/6
This is a formula
Formula n (n + 1) (2n + 1) / 6
If you want to prove the process, I can send the file to you, here uploaded several times all prompt failure!