Given cos (x-pai) = root 3 / 2, X belongs to [- Pai, Pai] to find the value of X

Given cos (x-pai) = root 3 / 2, X belongs to [- Pai, Pai] to find the value of X

cos(x-pai)=-cosx=√3/2
cosx=-√3/2
So x = - 5 π / 6, x = 5 π / 6
It is known that if cosa is equal to 5 / 4 and a is the angle of the fourth quadrant, what is the value of Tana
Cosa = 4 / 5 because it is the fourth quadrant, so x = 4, r = 5, y = - 3, Tan = Y / x, Tan = - 3 / 4
The positive proportional function parallel to the line y = - 2x + 3 is
y=-2x
(that is, y = KX + B, when B = 0, it is a positive proportional function)
y=-2x
Given that the eccentricity of the ellipse is 1 / 2 and the focus is (- 3,0), (3,0), then the equation of the ellipse is?
c= 3
If e = C / a = 1 / 2, then a = 6
b^2 = a^2 -c^2 =27
The elliptic equation is x ^ 2 / 36 + y ^ 2 / 27 = 1
Given that a is the second quadrant angle and cosa = - 4 / 5, the value of Tana is obtained
sina=√（1-cos²a）=±3/5
∵ A is the second quadrant angle
∴sina=3/5
∴tana=sina/cosa=3/5÷(-4/5)=-3/4
The analytic expression of the positive proportion function with the scale coefficient of - 3 is
The positive scaling function is y = KX
The proportion coefficient k = - 3
y=-3x
y=-3x
y=-3x
Given the two foci of the ellipse (- 2,0) (2,0) and the ellipse passing through (5 / 2,3 / 2), the equation of the ellipse is solved
Two focal points of known ellipse (- 2,0) (2,0)
C=2
And the ellipse passes through (5 / 2,3 / 2),
Let the equation be: x ^ 2 / A ^ 2 + y ^ 2 / b ^ 2 = 1
(5/2)^2/a^2+(3/2)^2/b^2=1.(1)
a^2-b^2=c^2.(2)
b^2=5
a^2=9
So x ^ 2 / 9 + y ^ 2 / 5 = 1
Given that a is the angle of the second quadrant, Tana = 1 / 2, then cosa=
cosA=-2√5/5
Given the positive proportional function y = KX, the value of proportional coefficient K can be obtained through a (- 1,3), (1)
Fast! ~ (2) find a point P on the x-axis, make s △ Pao = 12, and get the point P coordinate
(1) Substituting (- k = 3,3) = - 1 / (- 3)
(2) Let the coordinates of point p be (x, y), then OP = the absolute value of X
The bottom of △ Pao is po and the distance from point a to X axis is 3
Because s △ Pao = 1 / 2 * OP * 3
So the absolute value of x = 8
So x = - 8 or 8
And because point P is on the x-axis
So the coordinates of P are (8,0) or (- 8,0)
A focal point of the ellipse is f (1,0), and the equation of the ellipse is obtained by passing through the point (2,0)
I have to x ^ 2 / 4 + y ^ 2 / 3 = 1, right
That's right
Obviously a = 2, C = 1
So you did the right thing