1 / sin50 + radical 3 / cos50 thank

1 / sin50 + radical 3 / cos50 thank

The original formula = 2 * ((1 / 2) / sin50 + (sqrt (3) / 2) / cos50) = 2 * (sin30 / sin50 + cos30 / cos50) = 4 * (sin80 / sin100) = 4 * ((sin90 * cos10-cos90 * sin10) / (sin90 * cos10 + cos90 * sin10)) = 4 * (cos10 / cos10) = 4
1/sin50°+√3/cos50°
=(√3sin50°+cos50°)/(sin50°cos50°)
=4sin(50°+30°)/sin100°
=4sin80°/sin100°
=4sin(180°-100°)/sin100°
=4sin100°/sin100°
=4
What is the square of 4x-2x = 4x!
This equation has no real roots,
How to do cos80 ° cos50 ° + sin50 ° cos10 ° is the root of two
The original formula is sin10 ° cos50 ° + cos10 ° sin50 ° = sin (10 ° + 50 °) = sin60 ° = ^ 3 / 2
cos80°cos50°+sin50°cos10°
=1/2(cos 30+cos 130)+1/2( sin60 +sin 40)
=√3/4-sin40+√3/4+1/2sin40 （cos a =sin(90-a) )
=√3/2
Cos80 ° cos50 ° + sin50 ° cos10 ° = sin10 ° cos50 ° + sin50 ° cos10 ° = sin (10 + 50) ° = two thirds root sign three
I didn't learn
sin50°*cos50°=1/2sin100°
Isn't this the double angle formula?
2sinacosa=sin2a
∴sin50cos50=2\sin(2×50)=2\sin100
The square of x plus 4 equals 4x to find X
x²-4x+4=0
(x-2)²=0
So x = 2
X square + 4 = 4x, that is, x square - 4x + 4 = 0, (X-2) square = 0, x = 2
x²+4=4x
Then x & # 178; - 4x + 4 = 0
(x-2)²=0
So X1 = x2 = 2
I wish you progress in your study!
X^2+4=4X
X^2-4X+4=0
〖(X-2)〗^2=0
X=2
I hope you are satisfied~
X^2+4=4X
That is x ^ 2-4x + 4 = 0
(X-2)^2=0
X=2
How much is cos30?
Root of two sign 3 (sin 30 ° is 1 / 2)
2 (COS 50 ° - Sin 50 °)
√2（cos50°-sin50°）
=√2*√2（cos50°cos45°-sin50°sin45°）
=2cos(95°)
=-2sin5°
√2（cos50°-sin50°）
=2(√2/2cos50°-√2/2sin50°)
=2(sin45°cos50°-cos45°sin50°)
=2sin(45°-50°)
=2sin(-5°)
=-2sin5°
The square of 4x plus 1 plus (_ ）Equal to (_ Plus_ ）Square of
On the complete square formula--------------
Complete square formula
4x²+1+4x
=(2x+1)²
What is cos30 degrees
cos30=√3/2.
Find 1 / sin 50 degree + radical 3 / cos 50 degree
1/sin50°+√3/cos50°=(cos50°+√3sin50°)/(sin50°*cos50°)=2*[(1/2)cos50°+(√3/2)*sin50°]/(sin50°*cos50°)=2*sin(30+50)°/(1/2)*sin100°=4*sin80°/sin100°=4*sin100°/sin100°=4